the length of a rectangle, I, is six meters more than its width, w. if the perimeter of the rectangle is 36 meters, what is the
1 answer:
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Area = π × r2. Or, when you know the Diameter: A = (π/4) × D2. So A = 6π, which is 18.85. So A = 18.85. And here's the hand.
Answer:
Step-by-step explanation:
Given
See attachment
From the attachment, we have:
First, we need to calculate length LM,
Using Pythagoras theorem:
Collect Like Terms
Solving (a):
Substitute values for MN and LN
Solving (b):
Substitute values for LM and MN
Solving (c):
Substitute values for LN and LM
Solving (d):
Substitute values for LM and LN
