Question

How many atoms are in 35.5 g of chlorine?

Answer 1

35.5 g of chlorine is 1 mole of chlorine.

The answer is Avogadro's Number 6.02 x 10^23 atoms. 1 mole of every element has this number of atoms.

Answer 2

Answer: Option (B) is the correct answer.

Explanation:

According to Avogadro's number, one mole of a substance contains $6.022 \times 10^{23}$ atoms or molecules.

As molar mass of chlorine is 35.5 g/mol. Hence, calculate its number of moles as follows.

                   No. of moles = $\frac{mass}{\text{molar mass}}$

                                         = $\frac{35.5 g}{35.5 g/mol}$

                                         = 1 mol

Therefore, number of atoms present in 1.01 mol are calculated as follows.

                           $1 mol \times 6.022 \times 10^{23}$ atoms/mol

                              = $6.02 \times 10^{23}$ atoms

Therefore, we can conclude that there are $6.02 \times 10^{23}$ atoms in 35.5 g of chlorine.