Answer:
110 km an hour
Step-by-step explanation:
![\bf \cfrac{(x-2)(x+3)}{2x+2}\implies \cfrac{x^2+x-6}{2x+2}~~ \begin{array}{llll} \leftarrow \textit{2nd degree polynomial}\\ \leftarrow \textit{1st degree polynomial} \end{array} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{vertical asymptote}}{2x+2=0}\implies 2x=-2\implies x=-\cfrac{2}{2}\implies x=-1](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B%28x-2%29%28x%2B3%29%7D%7B2x%2B2%7D%5Cimplies%20%5Ccfrac%7Bx%5E2%2Bx-6%7D%7B2x%2B2%7D~~%20%5Cbegin%7Barray%7D%7Bllll%7D%20%5Cleftarrow%20%5Ctextit%7B2nd%20degree%20polynomial%7D%5C%5C%20%5Cleftarrow%20%5Ctextit%7B1st%20degree%20polynomial%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bvertical%20asymptote%7D%7D%7B2x%2B2%3D0%7D%5Cimplies%202x%3D-2%5Cimplies%20x%3D-%5Ccfrac%7B2%7D%7B2%7D%5Cimplies%20x%3D-1)
when the degree of the numerator is greater than the denominator's, then it has no horizontal asymptotes.
quick note:
when the degree of the numerator is 1 higher than the degree of the denominator, then it has an slant-asymptote, so this one has a slant-asymptote.
In a circle H with a measure of angle ∠GKJ = 27°. Then the measure of angle ∠GHJ will be 54°
<h3>What is a circle?</h3>
It is the center of an equidistant point drawn from the center. The radius of a circle is the distance between the center and the circumference.
In a circle H with a measure of angle ∠GKJ = 27°.
Then the measure of angle ∠GHJ will be
We know that a chord's slope in the centre is double that of the chord's slope at the perimeter.
Then we have
∠GHJ = 2 x ∠GKJ
∠GHJ = 2 x 27°
∠GHJ = 54°
More about the circle link is given below.
brainly.com/question/11833983
#SPJ1
Answer:
slope- 3/4. equation- y=3/4x+1
Step-by-step explanation:
to get the equation, you use the formula y=mx+b, where m is the slope and b is the y intercept, which means it is where the line touches the y axis
