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ella [17]
3 years ago
13

What are the different ways to write 8x8x8x8x8x8x8x8

Mathematics
1 answer:
Dafna1 [17]3 years ago
8 0
8*8*8 etc.
8 to the power of 8
The actual answer
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Can you figure out the formula
puteri [66]

If "a" and "b" are two values of x-coordinate, and "m" is the midpoint between them, it means the distance from one end to the midpoint is the same as the distance from the midpoint to the other end

... a-m = m-b

When we add m+b to this equation, we get

... a+b = 2m

Solving for m gives

... m = (a+b)/2

This applies to y-coordinates as well. So ...

... The midpoint between (x1, y1) and (x2, y2) is ((x1+x2)/2, (y1+y2)/2)

_____

Jennifer had (x1, y1) = (-4, 10) and (x2, y2) = (-2, 6). So her calculation would be

... midpoint = ((-4-2)/2, (10+6)/2) = (-6/2, 16/2) = (-3, 8)

Brandon had (x1, y1) = (9, -4) and (x2, y2) = (-12, 8). So his calculation would be

... midpoint = ((9-12)/2, (-4+8)/2) = (-3/2, 4/2) = (-1.5, 2)

4 0
3 years ago
Divide 1.20m in the ratio 2:3:4 in a clear way
tatuchka [14]
2:3:4 gives 9 equal parts.
1.20 divided by 9 is 0.133.

2 * 0.133 would be 0.266m
3 * 0.133 would be 0.399m
4 * 0.133 would be 0.533m

To check this calculate 0.533 + 0.399 + 0.266 would be 1.198m (close enough)
4 0
4 years ago
Helppp can someone solve this please
Norma-Jean [14]

Answer:

\displaystyle x=-15

Step-by-step explanation:

<u>Solution Of A System Of Equations </u>

A system of linear equations is given as

\displaystyle \left\{\begin{matrix}ax+by=c\\ dx+ey=f\end{matrix}\right.

There are many methods to solve them. We will use the method of reduction

The given system is

\displaystyle \left\{\begin{matrix}2x+3y=45\\ x+y=10\end{matrix}\right.

Multiplying the second equation by -3

\displaystyle \left\{\begin{matrix}2x+3y=45\\ -3x-3y=-30\end{matrix}\right.

Adding the resulting equations

\displaystyle -x=15

\displaystyle x=-15

5 0
3 years ago
How to do the problem
SpyIntel [72]
The top and sides of the cylinder have an area of pr^2+2prh, but the pr^2 of the top is also removed from the cube which has an area of 6s^2.

A=6s^2+2prh

A=6*36+2p4*1

A=216+8p in^2

A≈241.13 in^2 (to nearest one-hundredth)

Note that I did not include the area of the cylinder that touches the cube...
3 0
3 years ago
a circle has a center at (3,5) the point (3,8) is on the circle what is the circumference of the circle to the nearest tenth of
kogti [31]
You need to use the distance formula to find the radius of the circle.

d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2} \\  \\ d = \sqrt{(3-3)^2 + (8-5)^2} \\  \\ d = \sqrt{0^2+3^2} \\  \\ d = \sqrt{9} = 3

The radius is 3.

The circumference is 2 \pi r

= 6\pi \\  \\ =18.8
3 0
3 years ago
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