1 answer:
The top and sides of the cylinder have an area of pr^2+2prh, but the pr^2 of the top is also removed from the cube which has an area of 6s^2.
A=6s^2+2prh
A=6*36+2p4*1
A=216+8p in^2
A≈241.13 in^2 (to nearest one-hundredth)
Note that I did not include the area of the cylinder that touches the cube...
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Hope this helps. - M
I could help you with math
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