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3 years ago

How to do the problem

Mathematics

1 answer:

SpyIntel [72]3 years ago

3 0

The top and sides of the cylinder have an area of pr^2+2prh, but the pr^2 of the top is also removed from the cube which has an area of 6s^2.

A=6s^2+2prh

A=6*36+2p4*1

A=216+8p in^2

A≈241.13 in^2 (to nearest one-hundredth)

Note that I did not include the area of the cylinder that touches the cube...

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the area of the base is:
$\frac{ab}{2}$
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2 years ago

What is the length of MN

rusak2 [61]

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3x = x + 10

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