Question

How to do the problem

Answer 1

The top and sides of the cylinder have an area of pr^2+2prh, but the pr^2 of the top is also removed from the cube which has an area of 6s^2.

A=6s^2+2prh

A=6*36+2p4*1

A=216+8p in^2

A≈241.13 in^2 (to nearest one-hundredth)

Note that I did not include the area of the cylinder that touches the cube...