1 answer:
The top and sides of the cylinder have an area of pr^2+2prh, but the pr^2 of the top is also removed from the cube which has an area of 6s^2.
A=6s^2+2prh
A=6*36+2p4*1
A=216+8p in^2
A≈241.13 in^2 (to nearest one-hundredth)
Note that I did not include the area of the cylinder that touches the cube...
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Answer:
52.4
Step-by-step explanation:
Arc length = 2πr(θ/360)
r = 10
θ = 300°
Arc length = 2π(10)(300/360) = 20π(0.8333) = 16.666π ≈ 52.36
2/3 x 5 = 3
the ratio from 4 to 20 is 5, then you multiply it by the original amount
so it's 3
That's the Kolakovski sequence,
Answer:
< B = 180-30-65=85°
< E = 85°
< D = 30°
< C = 65°
BC = 20/35 × 28 = 16
Answer:
45*
Step-by-step explanation:
This is because angles of a triangle like this need to be 135* total. So 135/3 is 45*
