The largest consecutive integers whose sum is less than 46 are x= 21 and x+1=22
Step-by-step explanation:
Let the integers be:
x and x+1
The sum of these integers is less than 46
Solving and finding value of x:
So, the integers will be less than 22.5
The largest numbers are: 21 and 22
So, the largest consecutive integers whose sum is less than 46 are x= 21 and x+1=22
Keywords: Finding integers
Learn more about finding integers at:
#learnwithBrainly
Answer:
19.1
Step-by-step explanation:
i took the testttttt
Answer:
5/9 & -10/3
Step-by-step explanation:
Set each to 0 and solve:
9x-5 = 0
9x=5
x=5/9
6x+20=0
6x=-20
x=-20/6
x= -10/3 or -3 1/3
Answer:
a = -3
Step-by-step explanation:
-2(a-3)=12
distribute the -2 to the terms in the paranthesis
-2a + 6 = 12
minus 6 both sides
-2a = 6
divide -2 both sides to isolate a
a = -3
I hope this was helpful (:
2x+4y=16
x-7=-4y
4y=16-2x
<span>4y=16-2(-4y+7)
4y=16+8y-14
-4y=2
-4y/-4=2/-4
<u>y=-0,5</u>
2x=16-4(-0,5)
2x=16+2
2x/2=18/2
<u>x=9
</u>
C</span>
