Answer:
Since we know that ABCD ~ EFGH, we have the ratios:
EF/AB = GH/CD
=> 0.4/1.2 = x/1.8
=> x = (1.8 . 0.4)/1.2 = 0.6
So x = 0.6
Given that <span>For
a certain model of car the distance

required to stop the vehicle if
it is traveling at

mi/h is given by the formula
![d=v+\frac{v^2}{20}, where [tex]d](https://tex.z-dn.net/?f=d%3Dv%2B%5Cfrac%7Bv%5E2%7D%7B20%7D%2C%20where%20%5Btex%5Dd%20)
is measured in feet.
If Kerry wants her stopping distance not to exceed 75
ft, then the range of speeds (in mi/h) can she travel is obtained as follows:

Therefore, the range of speed she can travel is

</span>
Answer:
59/20 cups
Step-by-step explanation:
5 3/10
8 1/4
Common denimainator is 40
5 3/10 = 5 12/40
8 1/4 = 8 10/40
Now we can subtract:
330/40-212/40=118/40
118/40= 59/20 cups
Sorry if I spelled some words wrong