When the velocity goes from 40km/h to 20 km/h, the kinetic energy decreases by a factor of 4.
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What happens to the kinetic energy?</h3>
We know that the kinetic energy depends of the square of the velocity. Thus, if we decrease the velocity from 40km/h to 20km/h, then the kinetic energy decreases.
Remember that the kinetic energy is:
K = (m/2)*v²
Where m is the mass.
The initial kinetic energy is:
K = (m/2)*(40km/h)²
The final kinetic energy is:
K' = (m/2)*(20km/h)²
The quotient gives:
K/K' = [ (m/2)*(40km/h)²]/[ (m/2)*(20km/h)²]
K/K' = (40km/h)²/(20km/h)² = 4
So the kinetic energy decreases by a factor of 4.
Learn more about kinetic energy:
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The answer would be 85% in percent and 0.85 in decimal
Answer:
(2^2)3 = 2^6
(2^3)2 = 2^6
Step-by-step explanation:
There are various exponent rules. The problems that you were assigned must follow the power of a power rule:
(x^a)^b = x^a*b
Exponents must be multiplied according to this rule. Hope this helps.
Answer:
y=21-3x and y=18-2x
Step-by-step explanation:
Ok, so we have candle A, which is 21 inches and burns 3 inches every hour. in slope-intercept form, the hours would be the x, the 21 is our y intercept. So the first equatio would be y=-3x+21 (negative slope, because the height of the candle is going down). Candle b, which is 18 inches, burns away 2 inches each hour. We can make -2 the slope (negative 2, since the candle is being burned away, not being added to), and the 18 our y intercept. So the two equations would be
y=21-3x
and
y=18-2x
hope this helps!