Answer:
The fraction of heterozygous individuals in the population is 32/100 that equals 0.32 which is the genotipic proportion for these endividuals.
Explanation:
According to Hardy-Weinberg, the allelic frequencies in a locus are represented as p and q, referring to the alleles. The genotypic frequencies after one generation are p² (Homozygous for allele p), 2pq (Heterozygous), q² (Homozygous for the allele q). Populations in H-W equilibrium will get the same allelic frequencies generation after generation. The sum of these allelic frequencies equals 1, this is p + q = 1.
In the exposed example, the r-6 allelic frequency is 0,2. This means that if r-6=0.2, then the other allele frequency (R) is=0.8, and the sum of both the allelic frequencies equals one. This is:
p + q = 1
r-6 + R = 1
0.2 + 0.8 = 1
Then, the genotypic proportion for the homozygous individuals RR is 0.8 ² = 0.64
The genotypic proportion for the homozygous individuals r-6r-6 is 0.2² = 0.04
And the genotypic proportion for heterozygous individuals Rr-6 is 2xRxr-6 = 2 x 0.8 x 0.2 = 0.32
I'm assuming you meant and frailness not fertility, in which case it is the oldest old period
Any property that describes how a substance reacts with another substance when forming a new substance is the Property of Reactivity
.
Explanation:
The ability of substance to readily react with other substance to produce new product is called as reactivity.
It describes about different methods used by the reactants to form new product.
Sometimes one single reactant gives rise to two different products as in splitting of water during which the following reaction takes place:
H_2 O →2H_2 + O
On contrary, two substance combines together to give rise to one single product as:
2 Mg + O_2 →2MgO
