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3 years ago

Multiply the polynomial. (4x+2)(x-2) PLEASE HELP!!! ASAP!!!

Mathematics

2 answers:

OLga [1]3 years ago

5 0

Answer:4x2−6x−4

Step-by-step explanation:

(4x+2)(x−2)

=(4x+2)(x+−2)

=(4x)(x)+(4x)(−2)+(2)(x)+(2)(−2)

=4x2−8x+2x−4

=4x2−6x−4

densk [106]3 years ago

3 0

Answer:

(4x+2)(x-2)

= 4x(x-2) +2(x-2)

=4x^2-8x + 2x-4

=4x^2 - 6x -4

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Dana would need 75 pickets of each color to have an equal amount.

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3 years ago

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12. Jenna bought books for $3 each and a game for $5. She spent a total of $26. How many books

blondinia [14]

Answer: 7 books

Step-by-step explanation:

Start by subtracting 26 and 5 which gives you 21

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3 years ago

Use a graphing utility to graph the function and visually estimate the limits.

levacccp [35]

The value of the $\lim_{x \to 0} f(x)$ and $\lim_{x \to \frac{\pi }{3} } f(x)$ are 0 and 1.153 .

<h3></h3><h3>What is the limiting value of a function?</h3>

Limiting Value of a Function. The function's limit is the value of the function as its independent variable, such as x approaches a certain value called the limiting value. For simple equations, this is similar to finding out the value of y when x has a unique value.

Given that,

f(x) = $4x cos x$

First to calculate the limit value of the given function at x=0.

$\lim_{x \to 0} f(x)$ = $\lim_{x \to 0} 4x cosx$

= 4×0×1 (∵ cos0 = 1)

$\lim_{x \to 0} f(x)$ = 0

Similarly,

$\lim_{x \to \frac{\pi }{3} } f(x)$ = $\lim_{x \to \frac{\pi }{3} } 4x cosx$

= 4× $\frac{\pi }{3}$ ×cos $\frac{\pi }{3}$

= 4× $\frac{\pi }{3}$ × $\frac{1}{2}$ (∵cos60° = $\frac{1}{2}$ )

$\lim_{x \to \frac{\pi }{3} } f(x)$ = 1.153

Hence, The value of the $\lim_{x \to 0} f(x)$ and $\lim_{x \to \frac{\pi }{3} } f(x)$ are 0 and 1.153.

To learn more about the limit of the function from the given link:

brainly.com/question/23935467

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1 year ago

NEED HELP Find values for a, b, c, and d so that the following matrix product equals the 2X2 identity matrix. Explain or show ho

ehidna [41]

We want to find the values of a, b, c, and d such that the given matrix product is equal to a 2x2 identity matrix. We will solve a system of equations to find:

b = 1
a = -1
c = -2
d = -1

<h3>Presenting the equation:</h3>

Basically, we want to solve:

$\left[\begin{array}{cc}-1&2\\a&1\end{array}\right]*\left[\begin{array}{cc}b&c\\1&d\end{array}\right] = \left[\begin{array}{cc}1&0\\0&1\end{array}\right]$

The matrix product will be:

$\left[\begin{array}{cc}-b + 2&-c + 2d\\a*b + 1&a*c + d\end{array}\right]$

Then we must have:

-b + 2 = 1

This means that:

b = 2 - 1 = 1

b = 1

We also need to have:

a*b + 1 = 0

we know the value of b, so we just have:

a*1 + b = 0

a = -1

Now the two remaining equations are:

-c + 2d = 0

a*c + d = 1

Replacing the value of a we get:

-c + 2d = 0

-c + d = 1

Isolating c in the first equation we get:

c = 2d

Replacing that in the other equation we get:

-(2d) + d = 1

-d = 1

d = -1

Then:

c = 2d = 2*(-1) = -2

c = -2

So the values are:

b = 1
a = -1
c = -2
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3 years ago

What is 4 to the second power times 4 to the fifth power

Tpy6a [65]

Answer:

none

Step-by-step explanation:

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3 years ago

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