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3 years ago

What is two thirds takeaway a half?

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

8 0

$\displaystyle \frac{2}{3} - \frac{1}{2} = \frac{4}{6} - \frac{3}{6} = \frac{1}{6}$

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What is the value of 6 + 2x when x = 5? (A) 4 (B) 13 (C)16 (D) 40

jasenka [17]

so x=5

substituting for x in the equation we get:

$6+2 \times 5 \\ = 6 + 10 = \\ = 16$

Ans C: 16

4 0

3 years ago

Find the sum of these two fractions. 12 3/4 and 4 1/9

Nat2105 [25]

Answer:

12.75 and 4.11111111111

7 0

3 years ago

Whoops i forgot to read the lesson :P 30 points

andriy [413]

Step-by-step explanation:

I'll do 2.

Alright,Alex let say we have factored a quadratic into two binomial, for example

$(5x + 3)(6x - 4)$

If we set both of those equal to zero

$(5x + 3)(6x + 4) = 0$

We can used the zero product property in this case to find the roots of the quadratic equation.

This means that

$if \: ab = 0 \: then \: a = 0 \: and \: b = 0$

This means we set each binomal equal to zero to find it root.

$5x + 3 = 0$

$5x = - 3$

$x = - \frac{3}{5}$

$6x + 4 = 0$

$6x = - 4$

$x = - \frac{2}{3}$

So our roots are negative 3/5 and negative 2/3 using zero product property

6 0

3 years ago

Write the equation of a line that has a slope of 4 and goes through the point (1, -2)

Genrish500 [490]

Mark me as brainliest please! :)

The point-slope form of equation is
y
+
4
=
6
⋅
(
x
−
3
)
Explanation:
Point - Slope form of a linear equation is
(
y
−
y
1
)
=
m
⋅
(
x
−
x
1
)
Given : Slope
m
=
6
, Point
(
x
1
,
y
1
)
=
(
3
,
−
4
)
The point-slope form of equation is
y
+
4
=
6
⋅
(
x
−
3
)

8 0

3 years ago

Can I get some help please? Thanks!

quester [9]

An ellipse (oval shape) is expressed by the following equation:

$\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2}=1$ where h is the x coordinate of the center and k is the y coordinate of the center. Furthermore, a is the horizontal distance from the center, and b is the vertical distance from the center. Lastly, c is the distance from the center to one of the foci (they are spaced apart equally).

We can find the foci by using $a^2 - b^2 = c^2$

36 - 11 = $c^2$

$c = \sqrt{25} = 5$

Since the k value in this case is 0, the y value of both foci are 0. Also, since h and k are both 0, we know the center of the ellipse is at the origin.

So the foci are (-5, 0) and (5, 0)

Hope this helps :)

3 0

3 years ago