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3 years ago

Simplify. 5 - [ - ( - 2)]

Mathematics

2 answers:

Nimfa-mama [501]3 years ago

6 0

Answer:

Step-by-step explanation:

1. A - times a - equals a +, which means [-(-2)] equals (2)

2. 5- (2) equals 5 - 2

3. 5-2= 3

Svetach [21]3 years ago

5 0

Answer:

Step-by-step explanation:

As you see in the equation, there is a simple rule to apply in any equation make you confuse with - or + symbol. When 2 minus symbol ( - ) stand together, it would become positive or plus symbol (+), so in this situation:

5 - [ - ( - 2)]

= 5 - (+ 2)

= 5 - 2

= 3

Hope this help you :3

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The dimensions of a rectangle are 3 1/5cm by 5 5/6cm. What is the area of the rectangle?

andreyandreev [35.5K]

Answer: C. 18 2/3cm

Explanation:

Area of rectangle = length x width

After you set up the fractions:

96/30 x 175/30
= 16800/900
= 18.666e
= 18 2/3

5 0

3 years ago

Which expression is a difference of cubes? 9w^33-y^12 18p^15-q^21 36a^22-b^16 64c^15- a^26

LiRa [457]

we know that

A polynomial in the form $a^{3}-b^{3}$ is called adifference of cubes. Both terms must be a perfect cubes

Let's verify each case to determine the solution to the problem

case A) $9w^{33} -y^{12}$

we know that

$9=3^{2}$ ------> the term is not a perfect cube

$w^{33}=(w^{11})^{3}$ ------> the term is a perfect cube

$y^{12}=(y^{4})^{3}$ ------> the term is a perfect cube

therefore

The expression $9w^{33} -y^{12}$ is not a difference of cubes because the term $9$ is not a perfect cube

case B) $18p^{15} -q^{21}$

we know that

$18=2*3^{2}$ ------> the term is not a perfect cube

$p^{15}=(p^{5})^{3}$ ------> the term is a perfect cube

$q^{21}=(q^{7})^{3}$ ------> the term is a perfect cube

therefore

The expression $18p^{15} -q^{21}$ is not a difference of cubes because the term $18$ is not a perfect cube

case C) $36a^{22} -b^{16}$

we know that

$36=2^{2}*3^{2}$ ------> the term is not a perfect cube

$a^{22}$ ------> the term is not a perfect cube

$b^{16}$ ------> the term is not a perfect cube

therefore

The expression $36a^{22} -b^{16}$ is not a difference of cubes because all terms are not perfect cubes

case D) $64c^{15} -a^{26}$

we know that

$64=2^{6}=(2^{2})^{3}$ ------> the term is a perfect cube

$c^{15}=(c^{5})^{3}$ ------> the term is a perfect cube

$a^{26}$ ------> the term is not a perfect cube

therefore

The expression $64c^{15} -a^{26}$ is not a difference of cubes because the term $a^{26}$ is not a perfect cube

I'm adding a new case so I can better explain the problem

case E) $64c^{15} -d^{27}$

we know that

$64=2^{6}=(2^{2})^{3}$ ------> the term is a perfect cube

$c^{15}=(c^{5})^{3}$ ------> the term is a perfect cube

$d^{27}=(d^{9})^{3}$ ------> the term is a perfect cube

Substitute

$64c^{15} -d^{27}=((2^{2})(c^{5}))^{3}-(d^{9})^{3}$

therefore

The expression $64c^{15} -d^{27}$ is a difference of cubes because all terms are perfect cubes

5 0

3 years ago

Read 2 more answers

Find the angle measurements of the intersections for the two equations f(x) = 4x - 5 and g(x) = 2x^2 - 5.

murzikaleks [220]

Answer:

76° is the other one

Step-by-step explanation:

nope, no precise calculation here. the option are thankfully enough apart that solving it graphically is just fine. look at the screenshot. the upper intersection is the one with the 7° angle

the lower one is somewhat less than 90° :P

5 0

3 years ago

Please help!!! I need help!

GrogVix [38]

4x+5=8x-11 solve for X then plug back into 4x+5 for the measure of angle QST

8 0

4 years ago

Read 2 more answers

Solve this equation. 5x-2y=3 y=2x

insens350 [35]

Answer:

Step-by-step explanation:

5x-2y=3 when: y=2x

1. Plug in the y-value (y=2x) into the equation (5x-2y=3). The equation should then look like 5x-2(2x)=3

2. Simplify:

5x-2(2x)=3

5x-4x=3

1x=3

x=3

Check:

5x-2(2x)=3 (plug in the x-value you solved for: 3)

5(3)-2×2(3)=3

15-2×6=3

15-12=3

3=3

Hope this helped !

Cheers, Z

8 0

3 years ago