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Given
This is a one-tailed test.
Since the p-value of the sample statistic (0.00383) is less that the significant level (0.025), we reject the null hypothesis.
This is a one-tailed test.
Since the p-value of the sample statistic (0.00383) is less that the significant level (0.025), we reject the null hypothesis.
Using the z-distribution, as we are working with a proportion, it is found that the 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.
<h3>What is a confidence interval of proportions?</h3>A confidence interval of proportions is given by:
In which:
is the sample proportion.
- z is the critical value.
- n is the sample size.
In this problem, the parameters are:
The lower limit of this interval is:
The upper limit of this interval is:
The 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.
More can be learned about the z-distribution at brainly.com/question/25890103