Is it possible for a system of linear equations to have no solutions ?
2 answers:
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Answer:
Your(my) number is 40
Step-by-step explanation:
I. Given 80/something, + 13, * 5 = 75 when x is something
So [ + 13 ]5 = 75
[ + 65] = 75
= 75 - 65
= 10
400 = 10x
x = 40
II. Prove by replace 40 in x
[(80/40) + 13]5 = 75
[2 + 13] 5 = 75
(15)5 = 75
75 = 75 true
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