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neonofarm [45]
3 years ago
14

Is it possible for a system of linear equations to have no solutions ?

Mathematics
2 answers:
sveta [45]3 years ago
8 0
Yes it is possible,t<span>hey never intersect, so there is </span>no<span> point that lies on both lines, and </span>no solution<span> to the </span><span>system</span>
AveGali [126]3 years ago
4 0

Answer: true

Step-by-step explanation:

You might be interested in
An amount of $700 was invested at 7% for 7 months. What is the interest? Round your
Levart [38]

Answer:

49 dollars

Step-by-step explanation:

700 times .07

7 0
3 years ago
Hey, could someone please help me with this? Thanks.
Novosadov [1.4K]

Answer:

Part A: 1. (1, 0.5) 2. (2, 1) 3. (3, 1.5) 4. (4, 2) 5. (5, 2.5) 6. (6, 3)

Part B: Yes, this relation is in fact a function.

Part C: No, it would not be a function.

Step-by-step explanation:

Part A: Well, you start at 1 hr. right? yes. So then, at the very beginning at the problem, it says the candle burns at the rate of 0.5 in. per hour. So for 1 hour, the candle will burn .5 inches. At 2 hours, it will burn off 1 whole inch.

Part B:  1 hr. = .5 in. burn,  2 hrs. = 1 in. burns,  3 hrs. = 1.5 in. burns,  4 hrs. = 2 in. burns,  5 hrs.= 2.5 in. burns, 6 hrs. = 3  in. burns.

Part C:  1 hr.= .45 in. burn, 2 hrs. = .9 in burn,  3 hrs. = 1.35 in. burns, 4 hrs. = 1.8 in. burns, 5 hrs. = 2.25 in. burns, 6 hrs. = 2.7 in. burns.    It does not go at a constant rate. The number of inches are all over the place.

Hope this helps you out!! (:

4 0
3 years ago
Urgent please!!! I really don’t understand it, tysm to anyone who can answer thissss :))))
Tomtit [17]

Given:

The frequency distribution table.

To find:

The mean average score on a test.

Solution:

The frequency distribution table is

Marks (x_i)                   Frequency(f_i)                  f_ix_i

     x                                     a                               xa

     y                                     b                               yb

     z                                     c                               zc

  Sum                              a+b+c                          xa+yb+zc

Now, the mean average score on the test is

Mean=\dfrac{\sum f_ix_i}{\sum f_i}

Mean=\dfrac{xa+yb+zc}{a+b+c}

Therefore, the mean average score on the test is \dfrac{xa+yb+zc}{a+b+c}.

3 0
3 years ago
What is the missing term in the quadratic expression below?<br><br> (2x-3)(x-4)=2x^2+____ -12
cupoosta [38]

Answer:

ok

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
NEED HELP ASAP, WORTH 80PTS
sp2606 [1]

D

This is because the expression can be simplified to get the same result. -1+2log_4((1/4)x)

3 0
2 years ago
Read 2 more answers
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