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Dmitry_Shevchenko [17]
3 years ago
11

Alexis has a savings account that earns 2.1% interest compounded daily. If she opened the account 17 years ago with a deposit of

$2,914.72, how much interest has Alexis earned?
Mathematics
1 answer:
sergejj [24]3 years ago
5 0

Compound Interest Formula:  A = P(1 + r/n)^(n·t)

A = final amount                  r = rate, as a decimal (.021)                      t = number of years (17)

P = initial amount (2914.72)    n = number of times compounded per year (365)

A  =  2914.72(1 + .021/365)^(365·17)  =  $4165.20

Interest earned:  $4165.20 - $2914.72  =  $1250.48           <-----  Answer

You might want to recalculate this, attempting to handle leap years, by replacing the number of times compounded per year with 365.25 and see if that has an effect

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crimeas [40]
Circumference of a circle formula is 2\pir

2 × \pi × 80
=160 × <span>\pi 
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She skates 502.4 m.</span>
4 0
3 years ago
Which shows the following expression after the negative exponents have been eliminated?
belka [17]

Answer:

The given expression  \frac{a^3}{ab^{-4}} after the negative exponents have been eliminated becomes \frac{a^3b^{4}}{ab^{2}}

Step-by-step explanation:

Given expression \frac{a^3b^{-2}}{ab^{-4}}

We have to write expression after the negative exponents have been eliminated and  a ≠ 0 and b ≠ 0.

Consider the given expression \frac{a^3b^{-2}}{ab^{-4}}  

We have to eliminate the negative exponents,

Using  property of exponents, x^{-m}=\frac{1}{x^m}  we have ,

b^{-2}=\frac{1}{b^2} \\\\b^{-4}=\frac{1}{b^4}

Substitute, we get,

\frac{a^3}{ab^{-4}} becomes  \frac{a^3b^{4}}{ab^{2}}

Thus, the given expression  \frac{a^3}{ab^{-4}} after the negative exponents have been eliminated becomes \frac{a^3b^{4}}{ab^{2}}

5 0
4 years ago
Read 2 more answers
Find the quotient and remainder for52/8
Burka [1]
The answer 48 with a remainder of 4. Hope this works.
8 0
3 years ago
Passes through (3, 4) and (5, -4) how do I solve​
nikitadnepr [17]

Answer:

y = - 4x + 16

Step-by-step explanation:

Assuming you require the equation of the line passing through the points.

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (3, 4) and (x₂, y₂ ) = (5, - 4)

m = \frac{-4-4}{5-3} = \frac{-8}{2} = - 4, thus

y = - 4x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (3, 4), then

4 = - 12 + c ⇒ c = 4 + 12 = 16

y = - 4x + 16 ← equation of line

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3 years ago
Plss help I’ll give brainlist or what ever it’s called
Pachacha [2.7K]
1/4 i think hope that helps
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