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Juliette [100K]

3 years ago

15

Find x if 2, 6 , x are in continued proportion

1 answer:

zlopas [31]3 years ago

4 0

Do you have a picture if not you just mutilply and get 12 I think

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3/5 bigger or smaller than 1/5

Wewaii [24]

Imagine fractions as a pie. The bottom number is the total pieces of slices that make up the pie. The top number is how many you are served.

If there are a total of 5 pieces and you get 3 pieces of the pie, is that larger than getting 1 piece of the pie? Yes!

3 0

3 years ago

Quadrilateral ABCDABCDA, B, C, D is reflected across line mmm to create quadrilateral A'B'C'D'A

sveta [45]

Answer:

104

Step-by-step explanation:

4 0

3 years ago

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Given f(x) = x3 – 2x2 – x + 2, <br><br> the roots of f(x)

anyanavicka [17]

f(x) = x³ – 2x² – x + 2

0 = x3 – 2x2 – x + 2

(x-2)(x-1)(x+1)=0

x1=-1

x2=1

x3=2

5 0

3 years ago

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Please help with math problem

e-lub [12.9K]

Answer:

$a_0 = -8$

$a_1=-6$

$x^2 +y^2 -8x - 6y = 0$

Step-by-step explanation:

The equation of the circle has the following form

$x^2 + y^2 + a_0x + a_1y=0$

The equation of the circle has the following form

We know that the circle goes through the following points

(1, 7)

(8, 6)

(7, -1).

Then we substitute the values of x and y in the equation

<u>For (1, 7)</u>

$(1)^2 + (7)^2 + a_0(1) + a_1(7)=0$

$1 + 49 + a_0 + 7a_1=0$

$a_0 + 7a_1=-50$ (1)

<u>For (8, 6)</u>

$(8)^2 + (6)^2 + a_0(8) + a_1(6)=0$

$64 + 36 + 8a_0 + 6a_1=0$

$8a_0 + 6a_1= -100$ (2)

With these equations is enough to solve the system

$a_0 + 7a_1=-50$ (1)

$8a_0 + 6a_1= -100$ (2)

Multiply the equation (1) by -8 and add it to the equation (2)

$-8a_0 - 56a_1=400$ (1)

$8a_0 + 6a_1= -100$ (2)

-----------------------------------------------------

$-50a_1 = 300\\\\a_1 = -6$

Then

$a_0 + 7(-6) = -50\\\\a_0 = -50+42\\\\a_0=-8$

Finally the equation is:

$x^2 +y^2 -8x - 6y = 0$

7 0

3 years ago

Please help asap 20 pts

ddd [48]

B is the answer. If you solve for x, the values you get are 2.7077 and -0.422.

6 0

3 years ago

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