Answer:
110 words in 5 min, 220 words in 10 min
Step-by-step explanation:
y = mx (there is no intercept because you can't type anything in 0 minutes)
66 = 3m
m = 22
y = 22x
5 minutes:
y = 22(5) = 110 words
10 minutes:
y = 22(10) = 220 words
The size of the second application given the size of the first application and the expression ( x - 3.45 mb) for the size of the second application is 293.55 MB.
<h3>Equation</h3>
Let
- Size of the first application = x
- Size of the second application= x - 3.45 mb
For instance,
if the size of the first application is 297 MB
Size of the second application= x - 3.45 mb
= 297 MB - 3.45 MB
= 293.55 MB
Therefore, the size of the second application given the size of the first application and the expression for the size of the second application is 293.55 MB
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the answer is the third option, starting with degree 11.
Apparently there's no solution?? i tried solving it, and i also used a special calculator, but no solution came up
