Question

(-1, -7), 3x + 12y = -6 find the perpendicular line

Answer 1

Answer:

$\[y=4x-3\]$

Step-by-step explanation:

Equation of the given line: $\[3x+12y=-6\]$

Rewriting it in standard form: $\[12y=-3x-6\]$

=> $\[y=-\frac{3}{12}x-\frac{6}{12}\]$

Or, $\[y=-\frac{1}{4}x-\frac{1}{2}\]$

Slope of the line = $\[-\frac{1}{4}\]$

Slope of the perpendicular line = 4

So the equation of the perpendicular line:

$\[y=4x+c\]$

This passes through the point (-1,-7).Substituting in the equation:

$\[-7=4*(-1)+c\]$

=> $\[c=-7+4\]$

=> $\[c=-3\]$

So the equation of the line :

$\[y=4x-3\]$

Answer 2

Step-by-step explanation:

write equation in terms of x

y=(-6+3x)/12

from this equation u can see your gradient is 3/12 or 1/4

your perpendicular gradient is -1/m (m being the gradient of your main line)

so gradient of perpendicular= -4

since coordinate of main line is given, that point will also be on perpendicular.

so u have point and gradient so u can Calculate line equation

Y=MX+C

(-7)=(-4)(-1)+c

c=-11

y=-4x-11

^equation of perpendicular