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pickupchik [31]
4 years ago
13

Given frequent itemset l and subset s of l, prove that the confidence of the rule "s’ => (l - s’)" cannot be more than the co

nfidence of "s => (l - s)", where s’ is a subset of:_________
Mathematics
1 answer:
aniked [119]4 years ago
4 0

Answer:

the answer is I

Step-by-step explanation:

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3 years ago
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3 years ago
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alekssr [168]

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