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pickupchik [31]

4 years ago

13

Given frequent itemset l and subset s of l, prove that the confidence of the rule "s’ => (l - s’)" cannot be more than the co

nfidence of "s => (l - s)", where s’ is a subset of:_________

1 answer:

aniked [119]4 years ago

4 0

Answer:

the answer is I

Step-by-step explanation:

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The city council of Pine Bluffs is considering increasing the number of police in an effort to reduce crime. Before making a fin

nikdorinn [45]

Answer:

Part a

The regression equation is, $\hat y = 29.3877 - 0.9596x$

Part b

The number of crimes for a city at 20 police officers was appointed is approximately 10.

Step-by-step explanation:

<u>x y xy x² y²</u>

15 17 255 225 289

17 7 119 289 49

17 13 221 289 169

12 21 252 144 441

25 5 125 625 25

11 19 209 121 361

27 7 189 729 49

22 6 132 484 36

146 95 502 2906 1419

Therefore,

$\hat B_1=\frac{n \sum xy - (\sum x) (\sum y)}{n (\sum x^2) - (\sum x)^2}$

$= \frac{8(1502) - (146)(95)}{8(2906)-(146)^2} \\\\= \frac{-1854}{1932} \\\\= - 0.9596$

The calculation of the intercept coefficient is as follows:

$\hat B_0= \frac{\sum y }{n} - \hat B_1 (\frac{\sum x}{n} )$

$= \frac{95}{8} - (-0.9596)(\frac{146}{8} )\\\\= 11.875 + 17.5127\\\\= 29.3877$

The regression equation is, $\hat y = 29.3877 - 0.9596x$

b)

The calculation is as follows:

$\hat y= 29.3877 - 0.9596x\\\\= 29.3877-0.9596(20)\\\\=29.3877-19.1920\\\\=10.1957$

≅ 10

The number of crimes for a city at 20 police officers was appointed is approximately 10.

The number of crimes for a city at 20 police officers was appointed is approximately 10.

That is, the number of polices increases then the number of crimes will be decreases.

8 0

4 years ago

How to factorise 7x+14

gregori [183]

<span>7x+14 = 7(x+2)
_____________</span>

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4 years ago

The directrix is the point where the parabola changes direction?<br> True or False

sergij07 [2.7K]

False
Because the parabola

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4 years ago

What does this symbol mean in math ≈ ?

weeeeeb [17]

Approximately equal to symbol
And it’s mostly used in terms of numerical approximations

6 0

2 years ago

Read 2 more answers

For the following problem, assume that all given angles are in simplest form, so that if A is in QIV you may assume that 270° &l

d1i1m1o1n [39]

Answer:

Step-by-step explanation:

Given that angle A is in IV quadrant

So A/2 would be in II quadrant.

sin A = -1/3

cos A = $\sqrt{1-sin^2 A} =\frac{2\sqrt{2} }{3}$

(cos A is positive since in IV quadrant)

Using this we can find cos A/2

$cosA = 2cos^2 \frac{A}{2} -1\\Or cos \frac{A}{2} =-\sqrt{\frac{1+cosA}{2} } =-\sqrt{\frac{3+2\sqrt{2} }{6} }$

3 0

3 years ago