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pickupchik [31]

2 years ago

13

Given frequent itemset l and subset s of l, prove that the confidence of the rule "s’ => (l - s’)" cannot be more than the co

nfidence of "s => (l - s)", where s’ is a subset of:_________

1 answer:

aniked [119]2 years ago

4 0

Answer:

the answer is I

Step-by-step explanation:

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