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Setler79 [48]
3 years ago
12

Is that better is just need help

Mathematics
2 answers:
yawa3891 [41]3 years ago
5 0
#1 Mrs. Garcia is making 50 snacks for her 5th grade class. If she uses four 1-kilogram bags of dried fruit, how many of grams of fruit will she use for each snack? 

1 kilogram is equal to 1000 grams.
4 kilograms is equal to 4000 grams. 

You would need to divide the 4000 total grams by the 50 snack to get how many grams would be in each snack.
So you would do..

4000grams/50snacks = 80 grams each snack.

#3 Toni's recipe also calls for seasonings. She needs to stir in 215 milligrams of pepper and 437 milligrams of salt. What is the difference between the total amount of seasonings and 1 gram?

215 milligrams is equal to 0.215 grams
437 milligrams is equal to 0.437 grams 

So you would add these two together
0.215 + 0.437 = 0.652 grams
Then to find the difference you would subtract 0.652 grams from 1 gram
1 - 0.652 = 0.348 
0.348 is the difference.

Vsevolod [243]3 years ago
3 0
1. 20 .... Well if there is 1000 grams of fruit divide that by 50 which is 20
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Please answer thoroughly
aleksklad [387]

Answer:

Part A: 2k(2c2+5(2)-8c-20)

Part B: sorry i don't know how to do this part

Step-by-step explanation:

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:]

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3 years ago
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QUESTION 1
Kitty [74]

It's difficult to make out what the force and displacement vectors are supposed to be, so I'll generalize.

Let <em>θ</em> be the angle between the force vector <em>F</em> and the displacement vector <em>r</em>. The work <em>W</em> done by <em>F</em> in the direction of <em>r</em> is

<em>W</em> = <em>F</em> • <em>r</em> cos(<em>θ</em>)

The cosine of the angle between the vectors can be obtained from the dot product identity,

<em>a</em> • <em>b</em> = ||<em>a</em>|| ||<em>b</em>|| cos(<em>θ</em>)   ==>   cos(<em>θ</em>) = (<em>a</em> • <em>b</em>) / (||<em>a</em>|| ||<em>b</em>||)

so that

<em>W</em> = (<em>F</em> • <em>r</em>)² / (||<em>F</em>|| ||<em>r</em>||)

For instance, if <em>F</em> = 3<em>i</em> + <em>j</em> + <em>k</em> and <em>r</em> = 7<em>i</em> - 7<em>j</em> - <em>k</em> (which is my closest guess to the given vectors' components), then the work done by <em>F</em> along <em>r</em> is

<em>W</em> = ((3<em>i</em> + <em>j</em> + <em>k</em>) • (7<em>i</em> - 7<em>j</em> - <em>k</em>))² / (√(3² + 1² + 1²) √(7² + (-7)² + (-1)²))

==>   <em>W</em> ≈ 5.12 J

(assuming <em>F</em> and <em>r</em> are measured in Newtons (N) and meters (m), respectively).

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I don't get what you mean by "with decimals" but it would be 1
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