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ddd [48]
3 years ago
11

Solve. X^2+20x+100=50

Mathematics
1 answer:
choli [55]3 years ago
5 0
1. You con solve the quadratic equation x^2+20x+100=50<span> by following the proccedure below:
 
 2. Pass the number 50 from the right member to the left member. Then you obtain:
 
 x^2+20x+100-50=0
</span><span> x^2+20x+50=0
</span><span> 
 3. Then, you must apply the quadratic equation, which is:
 
 x=(-b±√(b^2-4ac))/2a
 
 </span><span>x^2+20x+50=0
</span><span> 
 a=1
 b=20
 c=50
 

  4. Therefore, when you simplify, the result is:
 
  -10</span><span>±5</span>√2   (It is the last option).<span>


 
 
 
 
 
 </span>
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The common difference of the sequence is -3 and the fifth term is 5

<h3>How to determine the common difference?</h3>

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<h3>How to determine the fifth term?</h3>

The fifth term is calculated as:

T5 = a + 4d

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Read more about arithmetic sequence at:

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