Answer:
(x+3)^2+(y+2)^2=80
Step-by-step explanation:
The buffer will probably be destroyed by the addition of HCN.
<h3>What is buffer solution?</h3>
A weak acid and the conjugate base of the weak acid, or a weak base and the conjugate acid of the weak base, are combined to form the buffer solution, a water-based solvent solution. They withstand being diluted or having modest amounts of acid or alkali added to them without changing their pH.
Given that a 1.0 l buffer solution is 0.15 m in HCN and 0.10 m in NaCN.
We need to find a action which one destroy the buffer solution.
A buffer is a substance made of salt and a weak acid that is beneficial. From the aforementioned chemicals, HCN is a potent acid and NaCN is a salt between HF and NaCN. Therefore, the buffer will probably be destroyed by the addition of HCN.
To learn more about buffer solution from the given link
brainly.com/question/22390063
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Ok so basically I dunno all the corr. coefict stuff, but...
in 10 sec it went for 4 to 8, that's doubled
then from 8 to 12 is, +4, 4×3
A. Just during these two intervals we have, y/x: 4/10, then 8/20, then 12/30
0.4, 0.4, 0.4, but then it goes 15/30 = 0.5
so it's not a perfect 100% (1.00) correlation, but it would be very close [I'd choose b) 0.99]
B. from 10-30mins, it went from 4 to 8 to 12
m = change in y ÷ change in x
m = (12-4)/(30-10) = 8/20 = 0.40
C. means that the rate there is 0.40 miles per min. steady, which is 0.40 miles/min × 60min/hr = 24mi/hr steadily without increase or decrease, but a slight decrease from 30-40
RARELY say Causation, Ehr on the side of caution... correlation when in doubt
The answer to your question is this graph (see attached).
Put the time
portion on the x-axis and the snowfall portion on the y-axis. It snowed lightly
for a while meaning it took some time for the snow to fall. From zero, move the
graph a little going to x-axis (to the right). Then it stopped, giving the
graph a gap (just maintain a short horizontal line) then snowed heavily,
meaning, the snowfall increases then it stops (move the graph to the x-axis a
little higher then another short horizontal line). Hope this helps you.
Answer:
a) 40 dollars
b) 480 dollars
Step-by-step explanation:
Given the average property tax on a three bedroom home in a certain community modelled by the equation T(x) =20x²+40x+600, the rate at which the property tax is increasing with respect to time in 2008 can be derived by solving for the function T'(x) at x=0
T'(x) = 2(20)x¹ + 40x° + 0
T'(x) = 40x+40
At x = 0,
T'(0) = 40(0)+40
T'(0) = 40
Hence the property tax was increasing at a rate of 40dollars with respect to the initial year (2008).
b) There are 4 years between 2008 and 2012. To know how much that the tax change between the years 2008 and 2012, we will find T(4) - T(0)
Given T(x) =20x²+40x+600
T(4) =20(4)²+40(4)+600
T(4) = 320+160+600
T(4) = 1080 dollars
Also T(0) =20(0)²+40(0)+600
T(0) = 0+0+600
T(0)= 600 dollars
T(4) - T(0) = 1080 - 600
T(4) - T(0) = 480 dollars
Hence, the tax has changed by $480 between 2008 and 2012
