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adoni [48]
3 years ago
5

Suppose customers in a certain queue are served one at a time sequentially, that the time for each individual customer is Expone

ntial, and the average service time per customer equals 12 minutes. (Assume service times are independent of each other.) The time, in minutes, until the next 3 services are completed is Gamma (more specifically, Erlang) with what shape and rate parameters?
Mathematics
1 answer:
alexandr402 [8]3 years ago
5 0

Answer:

The shape and rate parameters are \frac{1}{12} and 3.

Step-by-step explanation:

Let <em>X</em> = service time for each individual.

The average service time is, <em>β</em> = 12 minutes.

The random variable follows an Exponential distribution with parameter, \lambda=\frac{1}{\beta}=\frac{1}{12}.

The service time for the next 3 customers is,

<em>Z</em> = <em>X</em>₁ + <em>X</em>₂ + <em>X</em>₃

All the <em>X</em>_{i}'s are independent Exponential random variable.

The sum of independent Exponential random variables is known as a Gamma or Erlang random variable.

The random variable <em>Z</em> follows a Gamma distribution with parameters (<em>α</em>, <em>n</em>).

The parameters are:

\alpha =\lambda=\frac{1}{12}\\n=3

Thus, the shape and rate parameters are \frac{1}{12} and 3.

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Montano1993 [528]
A. 6 + 6 = 12
b. 7 + 8 = 15
c. 0 + 0 = 0
d. 5 + -5 = -10
4 0
3 years ago
Max went to the store and bought 22 apples. He bought twice as many red apples as he did green, and he bought one-third many yel
katrin [286]

Let the number of green apples bought be x


Green apples = x

Red apples = 2x

Yellow apples = 1/3 (2x) = 2/3 x


Total = 22 apples

x + 2x + 2/3 x = 22

11/3 x = 22

11x = 66

x = 6


Green apples = x = 6

Red apples = 2x = 2(6) = 12

Yellow apples = 2/3 (2x) = 2/3 (6) = 4


Answer: Green = 6, Red = 12, Yellow = 4

7 0
3 years ago
A line segment has the endpoints P(0, –6) and Q(–3, –7). Find the coordinates of its midpoint M.
rewona [7]

Answer:

i dont know.

Step-by-step explanation:

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5 0
2 years ago
What are the relative frequencies, to the nearest hundredth, of the rows of the two way table?
Nookie1986 [14]

Answer:            A         B

Group A        0.25      0.75

Group B        0.45      0.55

Step-by-step explanation:

Since we have given that

Number of people of A in Group A = 15

Number of people of B in Group A = 45

Number of people of A in Group B = 20

Number of people of B in Group B = 25

Total number of people in Group A = 15+45 = 60

Total number of people in Group B = 20+25 = 45

So, Relative frequencies will be given  below:

Relative frequency of A in Group A is given by

\frac{15}{60}=0.25

Relative frequency of B in Group A is given by

\frac{45}{60}=0.75

Relative frequency of A in Group B is given by

\frac{20}{45}=0.45

Relative frequency of B in Group B is given by

\frac{25}{45}=0.55

Hence,             A         B

Group A        0.25      0.75

Group B        0.45      0.55

5 0
3 years ago
11
barxatty [35]
No, because the lasts line of the work is not true. 5 and 11 are not equal.
6 0
3 years ago
Read 2 more answers
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