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3 years ago

Worth 100 points please give full answer❤️

Mathematics

2 answers:

Tpy6a [65]3 years ago

5 0

f'(x)= $\frac{18tx+20x-7x^{2} +63t+140}{(x^{2} +9t+20)^{2} }$

natta225 [31]3 years ago

4 0

Answer: f'(x)= x+r=9 over 2 x 7 = 126

because 9 x 2 = 18 x 7= 126

your answer is 126

Step-by-step explanation:

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The base is a square 16m 6m

Ostrovityanka [42]

base is a square 16m 6m

Step-by-step explanation:

A square is a regular quadrilateral and it has four equal sides and four equal angles (90 degree angle or right angles).

A square quadrilateral with vertices ABCD would be denoted by ABCD. The perimeter of a square (quadrilateral) is given by:

P = 4a

Where a is the length of each side.

Perimeter of the square:

P = 4a

P = 4 × 16 cm

P = 64 cm

Hence, the perimeter of square is 64 cm.

7 0

2 years ago

I need help on 5 and 6

Blizzard [7]

5. 4 rows of circles with 4 columns of circles

6. A Hexagon with 4 circles

8 0

2 years ago

A survey 3,000 who bought a new car showed that 900 had problems. What is the relative frequency of the people that had problems

Anit [1.1K]

Answer:

30%

Step-by-step explanation:

Presuming that "survey 3,000" is the total and "900" is the factor who had problems then dividing the total amount by the amount of problems like equal the relative frequency of people that had problems

Math:

Amount of people you had problems / Amount of people who bought the new car.

900 / 3000 = 0.3

Now you need to multiply by 100% (because % in this case is a unit/measurement)

0.3 * 100% = 30%

3 0

2 years ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

2 years ago

Granny visited the Eiffel Tower. It is 324 meters tall. The Statue of Liberty is 93 meters tall. What is the ratio of the height

Nataly_w [17]

324 : 93

simplified:

108 : 31

5 0

2 years ago