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3 years ago

What is the answer and the work to do it i am stuggling with it

Mathematics

1 answer:

Marina CMI [18]3 years ago

5 0

The perimeter is 123 ft. Because 29 plus 41 plus 24 plus 12 plus 17 equals 123. You add all of the numbers on the outside to get perimeter.

The Area is 781 ft. Because you have to split the shape into normals shapes like two rectangles and then multiply the outside numbers so
17 times 29 equals 493 and 24 times 12 equals 288. 493 plus 288 equals 781 which is the area

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Sow your work plz and thank you! Best answer gets brainliest!

ELEN [110]

First of all, a 2 foot kangaroo is casting a 7 foot shadow.
Next we do 7 divided by 2 which equals 3.5.
Since we know the shadow is going to be 3.5x the object size we have to divide its shadow by 3.5

14 divided by 3.5 is 4 so the Eucalyptus tree is 4ft long

Your answer=4ft

Hope this helps!

8 0

3 years ago

Read 2 more answers

562 ÷ Choose... = 14 R2

Zolol [24]

Answer:

7868

Step-by-step explanation:

⇒ This can be written algebraically (with a variable x) as:

562 ÷ x = 14

⇒ Convert the division as a fraction:

$\frac{562}{x}$ = 14

⇒ Multiply both sides by 562 to get rid of the fraction and to isolate the variable x:

562 · $\frac{562}{x}$ = 14 · 562

⇒ Simplify:

x = 7868

Answer: 7868

Hope this helps! :)

4 0

3 years ago

Which equation represents the relationship between the side length, x, and the perimeter, y? y = one-fourth x y = 4x y = x + 13.

elixir [45]

Answer: B.

Y = 4x

Step-by-step explanation:

Given that the side of a shape is x

The perimeter of the shape is y

Perimeter of a rectangle can be expressed as:

P = 2L + 2W

Where L = length and W = width

But if the shape is a square, and the side of the shape is x, then, the perimeter will be

P = 4x

Where perimeter P = Y

Therefore, perimeter Y will be;

Y = 4x

Therefore, the correct answer is B which is:

Y = 4x

4 0

3 years ago

Return to the credit card scenario of Exercise 12 (Section 2.2), and let C be the event that the selected student has an America

Nadya [2.5K]

Answer:

A. P = 0.73

B. P(A∩B∩C') = 0.22

C. P(B/A) = 0.5

P(A/B) = 0.75

D. P(A∩B/C) = 0.4

E. P(A∪B/C) = 0.85

Step-by-step explanation:

Let's call A the event that a student has a Visa card, B the event that a student has a MasterCard and C the event that a student has a American Express card. Additionally, let's call A' the event that a student hasn't a Visa card, B' the event that a student hasn't a MasterCard and C the event that a student hasn't a American Express card.

Then, with the given probabilities we can find the following probabilities:

P(A∩B∩C') = P(A∩B) - P(A∩B∩C) = 0.3 - 0.08 = 0.22

Where P(A∩B∩C') is the probability that a student has a Visa card and a Master Card but doesn't have a American Express, P(A∩B) is the probability that a student has a has a Visa card and a MasterCard and P(A∩B∩C) is the probability that a student has a Visa card, a MasterCard and a American Express card. At the same way, we can find:

P(A∩C∩B') = P(A∩C) - P(A∩B∩C) = 0.15 - 0.08 = 0.07

P(B∩C∩A') = P(B∩C) - P(A∩B∩C) = 0.1 - 0.08 = 0.02

P(A∩B'∩C') = P(A) - P(A∩B∩C') - P(A∩C∩B') - P(A∩B∩C)

= 0.6 - 0.22 - 0.07 - 0.08 = 0.23

P(B∩A'∩C') = P(B) - P(A∩B∩C') - P(B∩C∩A') - P(A∩B∩C)

= 0.4 - 0.22 - 0.02 - 0.08 = 0.08

P(C∩A'∩A') = P(C) - P(A∩C∩B') - P(B∩C∩A') - P(A∩B∩C)

= 0.2 - 0.07 - 0.02 - 0.08 = 0.03

A. the probability that the selected student has at least one of the three types of cards is calculated as:

P = P(A∩B∩C) + P(A∩B∩C') + P(A∩C∩B') + P(B∩C∩A') + P(A∩B'∩C') +

P(B∩A'∩C') + P(C∩A'∩A')

P = 0.08 + 0.22 + 0.07 + 0.02 + 0.23 + 0.08 + 0.03 = 0.73

B. The probability that the selected student has both a Visa card and a MasterCard but not an American Express card can be written as P(A∩B∩C') and it is equal to 0.22

C. P(B/A) is the probability that a student has a MasterCard given that he has a Visa Card. it is calculated as:

P(B/A) = P(A∩B)/P(A)

So, replacing values, we get:

P(B/A) = 0.3/0.6 = 0.5

At the same way, P(A/B) is the probability that a student has a Visa Card given that he has a MasterCard. it is calculated as:

P(A/B) = P(A∩B)/P(B) = 0.3/0.4 = 0.75

D. If a selected student has an American Express card, the probability that she or he also has both a Visa card and a MasterCard is written as P(A∩B/C), so it is calculated as:

P(A∩B/C) = P(A∩B∩C)/P(C) = 0.08/0.2 = 0.4

E. If a the selected student has an American Express card, the probability that she or he has at least one of the other two types of cards is written as P(A∪B/C) and it is calculated as:

P(A∪B/C) = P(A∪B∩C)/P(C)

Where P(A∪B∩C) = P(A∩B∩C)+P(B∩C∩A')+P(A∩C∩B')

So, P(A∪B∩C) = 0.08 + 0.07 + 0.02 = 0.17

Finally, P(A∪B/C) is:

P(A∪B/C) = 0.17/0.2 =0.85

4 0

3 years ago

E true.

katovenus [111]

I'm not sure where it starts and ends

5 0

3 years ago