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larisa86 [58]
3 years ago
10

Write the equation in standard form of a circle with center (-3,6), tangent to the y-axis.

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
8 0

Answer:

(x+3)^2+(y-6)^2=9

Step-by-step explanation:

The equation of a circle in standard form is written as

(x-a)^2+(y-b)^2=r^2

where

(a, b) are the coordinates of the center

r is the radius of the circle

In this problem, the circle is centered at (-3,6), so we have

a = -3

b = 6

Also, we know that the circle is tangent to the y-axis, and the x-coordinate of its center is 3: this means that the horizontal distance between the point of the circle tangent to the y-axis and the centre of the circle is 3, therefore the radius of the circle is 3.

So, the equation of this circle is:

(x-(-3))^2+(y-6)^2=3^2

(x+3)^2+(y-6)^2=9

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Find the equation of the line perpendicular to y =<br> 3x + 6 and containing the point (-9,-5).
neonofarm [45]

The equation of the line perpendicular to y =  3x + 6 and containing the point (-9,-5) is y = \frac{-1}{3}x - 8

<em><u>Solution:</u></em>

Given that line perpendicular to y =  3x + 6 and containing the point (-9, -5)

We have to find the equation of line

<em><u>The slope intercept form is given as:</u></em>

y = mx + c  ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

<em><u>Let us first find the slope of line</u></em>

The given equation of line is y = 3x + 6

On comparing the given equation of line y = 3x + 6 with eqn 1, we get,

m = 3

Thus the slope of given equation of line is 3

We know that <em>product of slopes of given line and slope of line perpendicular to given line is equal to -1</em>

Slope of given line \times slope of line perpendicular to given line = -1

3 \times \text{ slope of line perpendicular to given line }= -1

\text{ slope of line perpendicular to given line } = \frac{-1}{3}

Let us now find the equation of line with slope m = \frac{-1}{3} and containing the point (-9, -5)

Substitute m = \frac{-1}{3} and (x, y) = (-9, -5) in eqn 1

-5 = \frac{-1}{3}(-9) + c\\\\-5 = 3 + c\\\\c = -8

<em><u>Thus the required equation of line is:</u></em>

Substitute m = \frac{-1}{3} and c = -8 in eqn 1

y = \frac{-1}{3}x - 8

Thus the required equation of line perpendicular to given line is found

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Enrique can spend at most $2240 to renovate his home. One roll of wallpaper costs $32, and one can of paint costs $28. He needs
umka2103 [35]

The possible solution is having 30 rolls of wallpaper and 20 can of paints or 30 rolls of wallpaper with 46 can of paint.

<h3>Inequality</h3>

Inequality is the non equal comparison of two or more numbers and variables.

Let x represent the number of wallpapers and y represent the number of cans.

He needs at least 30 rolls of wallpaper and at least 20 cans of paint. Hence:

x ≥ 30   (1);

y ≥ 20    (2)

Also:

32x + 28y ≤ 2240    (3)

Plotting the 3 equations using geogebra online graphing tool, the possible solution is:

(30, 20), (30, 46)

The possible solution is having 30 rolls of wallpaper and 20 can of paints or 30 rolls of wallpaper with 46 can of paint.

Find out more on Inequality at: brainly.com/question/24372553

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