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tamaranim1 [39]
3 years ago
8

What base side length does the rectangular prism need to have the same volume??????

Mathematics
1 answer:
valkas [14]3 years ago
7 0
Because you know that both the rectangular prism and the rectangular prism have the same volume, you can divide 588 cm^3 by 12cm to find the area of the base and get 49 cm^2. The base of the rectangular prism is x^2 so to solve just find the square rootof 49 cm^2 to get the side lengths (7 cm).

Hope this helped
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Hello people ~
Luden [163]

Cone details:

  • height: h cm
  • radius: r cm

Sphere details:

  • radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

<u>Using Pythagoras Theorem</u>

(a)

TO² + TU² = OU²

(h-10)² + r² = 10²                                   [insert values]

r² = 10² - (h-10)²                                     [change sides]

r² = 100 - (h² -20h + 100)                       [expand]

r² = 100 - h² + 20h -100                        [simplify]

r² = 20h - h²                                          [shown]

r = √20h - h²                                       ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (\sqrt{20h - h^2})^2  \  ( h)

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (20h - h^2)  (h)

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (20 - h) (h) ( h)

\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)

To find maximum/minimum, we have to find first derivative.

(c)

<u>First derivative</u>

\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )

<u>apply chain rule</u>

\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}

<u>Equate the first derivative to zero, that is V'(x) = 0</u>

\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0

\Longrightarrow \sf 40h-3h^2=0

\Longrightarrow \sf h(40-3h)=0

\Longrightarrow \sf h=0, \ 40-3h=0

\Longrightarrow \sf  h=0,\:h=\dfrac{40}{3}<u />

<u>maximum volume:</u>                <u>when h = 40/3</u>

\sf \Longrightarrow max=  \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )

\sf \Longrightarrow maximum= 1241.123 \ cm^3

<u>minimum volume:</u>                 <u>when h = 0</u>

\sf \Longrightarrow min=  \dfrac{1}{3} \pi (0)^2(20-0)

\sf \Longrightarrow minimum=0 \ cm^3

6 0
2 years ago
Read 2 more answers
Is -0.025 greater or less than -0.14?
AlekseyPX

Answer:

less than

Step-by-step explanation:

-0.025 is further away from -0.14 in the number line.

8 0
3 years ago
n a survey, 480 people, or 75%, said they attended a movie at least once a month. How many people were surveyed
scoundrel [369]
Answer:

 640 people

Explanation:

480 people = 75 %
x people = 100%

480 : x = 75 : 100
75 x = 48,000
x = 48,000 : 75
x = 640

5 0
3 years ago
Read 2 more answers
HELP HELP PLEASE IMPORTANT
Yuliya22 [10]

Answer:

2010

Step-by-step explanation:

1/2(24)(20)=240

50*45=2250

2250-240=2010

6 0
3 years ago
A tennis ball is 2 inch in diameter. How many tennis ball will fill a room of 20ft by 16ft by 18ft if no space wasted?
krek1111 [17]

The number of tennis ball that will fill the room is <u>1,371 tennis balls.</u>

<em><u>Given</u></em>:

Diameter of ball (d) : 2 inch

Radius (r) = half of diameter = 1 inch

Dimension of room = 20ft by 16ft by 18ft

Number of balls that will fill the room = Volume of each ball/volume of the room

Volume of the ball = volume of a sphere = \frac{4}{3} \pi r^{3}

Where,

r = 1

let \pi = 3.14

<em>Substitute</em>:

Volume = \frac{4}{3} \times 3.14 \times 1^{3} \\Volume = 4.2in^{3}

Volume of the room = 20 \times 16 \times 18 \\

= 5,760

Therefore:

number of tennis balls that will fill the room = \frac{5,760}{4.2} = 1,371.4

Therefore, the number of tennis ball that will fil the room will be <u>approximately 1,371.</u>

Learn more about volume here:

brainly.com/question/16098833

7 0
2 years ago
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