Answer: i and lll
Step-by-step explanation:
Hi there!
Find the y-intercept by substituting in 0 for x:
f(0) = 0² + 2(0) + 3
Simplify:
f(0) = 3
This question is difficult to give a definite answer to because it's an approximation, but I estimate the solutions to be around x = 2.6 and x = -2.6.
When they ask for solutions of the graphed function they are asking for an approximation of where the graph intercepts the x-axis, and we can see it kind of intercepts in the middle of 2 and 3, except slightly closer to 3, which is why I estimated 2.6.
The graph also appears to be symmetrical, which means the solutions will be the same except one would be negative and one would be positive, which means the second solution would be -2.6.
I hope this helps! Let me know if you have any questions :)
Problem One
Call the radius of the second can = r
Call the height of the second can = h
Then the radius of the first can = 1/3 r
The height of the first can = 3*h
A1 / A2 = (2*pi*(1/3r)*(3h)] / [2*pi * r * h]
Here's what will cancel. The twos on the right will cancel. The 3 and 1/3 will multiply to one. The 2 r's will cancel. The h's will cancel. Finally, the pis will cancel
Result A1 / A2 = 1/1
The labels will be shaped differently, but they will occupy the same area.
Problem Two
It seems like the writer of the problem put some lids on the new solid that were not implied by the question.
If I understand the problem correctly, looking at it from the top you are sweeping out a circle for the lid on top and bottom, plus the center core of the cylinder.
One lid would be pi r^2 = pi w^2 and so 2 of them would be 2 pi w^2
The region between the lids would be 2 pi r h for the surface area which is 2pi w h
Put the 2 regions together and you get
Area = 2 pi w^2 + 2 pi w h
Answer: Upper left corner <<<<< Answer
Answer:
A)
Step-by-step explanation:
