We are given that we have $25 to pay for 6 fishing lures.
We can make an equality for this as follows:
Suppose price of one fishing lure is x dollars.
So we will use unitary method to find price of 6 fishing lures.
Price of 6 fishing lures = 6 * ( price of one fishing lure) = 6* x = 6x
Now we only have 25 dollars with us, so the price of 6 fishing lures has to be less than or equal to 25 dollars.
So creating an inequality,
Now in order to find price for one fishing lure, we have to solve this for x.
Dividing both sides by 6 we have,
Converting to decimal,
Answer : The price of one fishing lure must be less than or equal to $4.167
Answer:
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Step-by-stedcvp explanation: welcome to family fued
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Answer:
P = 0.05
Step-by-step explanation:
12 months * 30 days each = 360 days
From 306 days, we have to select 8 days = 360C8 ways(Total ways)
We want each days from different month. First, we have to select 8 month from 12 month = 12C8 ways
---By selecting 8 month, we will select a days from each month. That can be done in = 30C1 * 30C1 * .................30C1 (8 ways) [From a month with 30 days, we can select a day in 30C1 ways = 30 ways]
Therefore P = Number of ways of selecting each days from different month / Total number of ways
P = 12C8 * 30^8 / 360C8
P = 495 * 656100000000 / 6469697679132645
P = 0.0501985588982791
P = 0.05
Hence the probability that each day is from a different month is 0.05
Answer:
Step-by-step explanation:
N = 3rt^4 - 5rz
now factor r out
N = r(3t^4-5z)
divide by r on both sides
N/r = (3t^4 - 5z)
subtract (3t^4)
N/r - 3t^4 = -5z
now divide by -5 to isolate the variable (z)
= z
