Answer:
C
Step-by-step explanation:
Student 2 made an error with the distributive property.
Answer:
C
Step-by-step explanation:
- choose any 2 sets of corresponding values and use the formula
( y2 - y1 ) / ( x2 - x1 )
you'll get -3/4
<span><span>2<span><span>(x+3)</span>2</span>+1</span><span>2<span><span>(x+3)</span>2</span>+1</span></span>Reorder the right side of the equation to match the vertex form of a parabola.<span><span>y=2<span><span>(x+3)</span>2</span>+1</span><span>y=2<span><span>(x+3)</span>2</span>+1</span></span>Use the vertex form, <span><span>y=a<span><span>(x−h)</span>2</span>+k</span><span>y=a<span><span>(x-h)</span>2</span>+k</span></span>, to determine the values of <span>aa</span>, <span>hh</span>, and <span>kk</span>.<span><span>a=2</span><span>a=2</span></span><span><span>h=−3</span><span>h=-3</span></span><span><span>k=1</span><span>k=1</span></span>Find the vertex <span><span>(h,k)</span><span>(h,k)</span></span>.<span>(−3,1<span>) ...................................</span></span>
Answer/Step-by-step explanation:
Recall the acronym SOHCAHTOA. This is what we would apply as appropriate in each case.
8. θ = 40°
Opp = m
Adj = 20
Thus, apply TOA
Tan (θ) = opp/adj
Plug in the values
Tan (40) = m/20 (equation)
20×Tan(40) = m
m = 16.7820
9. θ = 22°
Hyp = w
Adj = 18
Thus, apply CAH
Cos (θ) = adj/hyp
Plug in the values
Cos 22 = 18/w (equation)
w×cos 22 = 18
w = 18/(cos 22)
w = 19.4136
10. θ = 35°
Hyp = 55
Opp = x
Thus, apply SOH
Sin θ = opp/hyp
Plug in the values
Sin 35 = x/55 (equation)
55×sin 35 = x
x = 31.5467
11. θ = 33°
Hyp = 19
Adj = x
Thus, apply CAH
Cos θ = adj/hyp
Plug in the values
Cos 33 = x/19 (equation)
19×cos 33 = x
x = 15.9347
12. θ = 17°
Opp = 7
Hyp = x
Thus, apply SOH
Sin θ = opp/hyp
Plug in the values
Sin 17 = 7/x (equation)
x×sin 17 = 7
x = 7/(sin 17)
x = 23.9421
13. θ = 40°
Opp = 15
Adj = x
Thus, apply TOA
Tan θ = opp/adj
Plug in the values
Tan 40 = 15/x (equation)
x×Tan 40 = 15
x = 15/(Tan 40)
x = 17.8763
Answer:
a. 35 Kilometres.
b. 60 litres.
c. 8150 sweets.
Step-by-step explanation:
<u>Given the following data;</u>
- Distance traveled = 770 km
- Number of days = 22 days
a. To find how many kilometres he traveled in one day;
770 km = 22 days
X km = 1 day
Cross-multiplying, we have;
22X = 770
X = 770/22
<em>X = 35 Kilometres.</em>
b. To find how many litres he would need to go 840 km;
1 litre = 14 kilometres
X litres = 840
Cross-multiplying, we have;
14X = 840
X = 840/14
<em>X = 60 litres.</em>
c. To find how many sweets are there in his car;
Number of sweet box, Ns = 326 boxes
Number of sweets in each box, Sw = 25 sweets
Total number of sweets = Ns * Sw
Total number of sweets = 326 * 25
<em>Total number of sweets = 8150 sweets.</em>
