Answer:
x = 2
x = -21
Step-by-step explanation:
Answer:
Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, ![[ab]_K](https://tex.z-dn.net/?f=%20%5Bab%5D_K%20)
is equal to ![[ba]_K](https://tex.z-dn.net/?f=%20%5Bba%5D_K%20)
, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.
Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, ![[ab]_H = [ba]_H](https://tex.z-dn.net/?f=%20%5Bab%5D_H%20%3D%20%5Bba%5D_H%20)
. Since a and b were generic elements of H, then H/G is abelian.
Answer:
10
Step-by-step explanation:
10y+15=7y+45
10y-7y=45-15
3y=30
y=10
hope it helps you!
Answer:
-5x
Step-by-step explanation:
Answer:
a) ∠2 and ∠4 are a linear pair
∠4 = 115°
b) ∠2 and ∠7 are alternate exterior angles
∠7 = 65°
c) ∠2 and ∠3 are vertical angles
∠3 = 65°
Step-by-step explanation:
Linear pair : a pair of adjacent angles formed when two lines intersect. The two angles of a linear pair are always supplementary (two angles whose measures add up to 180°)
Alternate exterior angles : when two parallel lines are cut by a transversal (a line that intersects two or more other, often parallel, lines), the resulting alternate exterior angles are <u>congruent</u>.
Vertical angles : a pair of opposite angles formed by intersecting lines. Vertical angles are always <u>congruent.</u>
a) ∠2 and ∠4 are a linear pair
⇒ ∠2 +∠4 = 180
⇒ 65 + ∠4 = 180
⇒ ∠4 = 180 - 65
⇒ ∠4 = 115°
b) ∠2 and ∠7 are alternate exterior angles
⇒ ∠2 ≅ ∠7
⇒ ∠7 = 65°
c) ∠2 and ∠3 are vertical angles
⇒ ∠2 ≅ ∠3
⇒ ∠3 = 65°
