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iren2701 [21]
3 years ago
15

What is the cube root of 0.008? A) 2 B) 0.2 C) 0.02 D) 0.002

Mathematics
1 answer:
bazaltina [42]3 years ago
7 0
Correct answer is 0.2

0.2 * 0.2 is 0.04
then 0.04 * 0.2 = 0.008

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1. What is the area of the triangle below?<br> 10 in.<br> 7 in.
Alex787 [66]

Hi

<u>The area of a triangle is </u>

\cfrac{base*height}{2}

If we plug in the given values, we get:

\frac{10*7}{2}

Multiply in the numerator:

\frac{70}{2}

Divide:

35

Therefore, the area of the triangle is 35 inches squared.

6 0
2 years ago
Read 2 more answers
Use the functions h(x) = 2x - 5 and t(x) = 6x + 4 to complete the function operations listed below.
Rom4ik [11]

Answer:

See below for answers (in bold) and explanations

Step-by-step explanation:

Part A: (h+t)(x) = h(x) + t(x) = (2x-5) + (6x+4) = 2x - 5 + 6x + 4 = 8x - 1

Part B: (h*t)(x) = h(x) * t(x) = (2x-5) * (6x+4) = (2x)(6x) + (2x)(4) + (-5)(6x) + (-5)(4) = 12x² + 8x - 30x - 20 = 12x² - 22x - 20

Part C: h(t(x)) = h(6x + 4) = 2(6x + 4) - 5 = 12x + 8 - 5 = 12x + 3

3 0
3 years ago
In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= root 2 cm.
Nata [24]

Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.

Let AD=x, Since given AB=3

                                     AD+DB=3

                                       x+DB = 3

                                        DB = 3-x

Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem

BC^{2} = DB^{2} +CD^{2}

BC^{2} = (3-x)^{2} +(\sqrt{2} )^{2}

BC^{2} =(3-x)^{2} +2

Since given AD=BC,let us plugin BC=x in above step.

x^{2} =(3-x)^{2} +2

x^{2} =9-6x+x^{2} +2

6x=11

x=\frac{11}{6}

Now we know AD=x=\frac{11}{6} and given CD=√2.

Let us apply Pythagoras theorem for ΔACD

AC^{2} =AD^{2} +DC^{2}

AC^{2} = (\frac{11}{6} )^{2} +(\sqrt{2} )^{2}

AC^{2} =\frac{193}{36}

AC=\sqrt{\frac{193}{36} } = 2.315cm

3 0
3 years ago
last week rafael drove m miles. this week he drove 153 miles. using m, write an expression for the total number of miles he drov
zzz [600]

The expression for the total number of miles he drove in the two weeks is m + 153

<h3>How to determine the expression for the total number of miles he drove in the two weeks?</h3>

The given parameters are

Last week = m miles

This week = 153 miles

The expression for the total number of miles he drove in the two weeks is

Expression = Last week + This week

This gives

Expression = m + 153

Hence, the expression for the total number of miles he drove in the two weeks is m + 153

Read more about expressions at

brainly.com/question/723406

#SPJ1

5 0
1 year ago
Pls helppppp 25 pt and brainiest for whoever answers it right.
defon
<h3><u>Given</u><u>:</u><u>-</u></h3>

  • Perimeter of parallelogram = 66 ft

  • One side,a = 3x + 1

  • Other side,b = 2x - 3

<h3><u>To</u><u> </u><u>find</u><u> </u><u>out</u><u>:</u><u>-</u></h3>

Find the longest side of a parallelogram.

<h3><u>Formula</u><u> </u><u>used</u><u>:</u><u>-</u></h3>

Perimeter of parallelogram = 2 ( a + b )

<h3><u>Solution:-</u><u> </u></h3>

We know that,

Perimeter of parallelogram = 2 ( a + b )

★ Substituting the values in the above formula,we get:

⇒ 66 = 2 ( 3x + 1 + 2x - 3 )

⇒ 66 = 2 ( 5x - 2 )

⇒ 66/2 = 5x - 2

⇒ 33 = 5x - 2

⇒ 5x - 2 = 33

⇒ 5x = 33 + 2

⇒ 5x = 35

⇒ x = 35/5

⇒ x = 7 ft

Now,

One side,a = 3x + 1

★ Putting the value of x

⇒ 3 × 7 + 1

⇒ 21 + 1

⇒ 22 ft

Other side,b = 2x - 3

★ Putting the value of x

⇒ 2 × 7 - 3

⇒ 14 - 3

⇒ 11 ft

Hence,the longest Side of given parallelogram is 22 ft ( 3x + 1 ) .

7 0
3 years ago
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