Question

What is the equation of the line that is parallel to the line y = -1/3 x + 4 and passes through the point (6, 5)? A: y = x + 3 B:y = x + 7 C: y = 3x – 13 D: y = 3x + 5

Answer 1

None of them are parallel but D. is perpendicular. I'm sorry if this doesn't help...

Answer 2

Answer:

$y=-\frac{1}{3}x+7$

Step-by-step explanation:

the equation of the line that is parallel to the line y = -1/3 x + 4 and passes through the point (6, 5)

$y=-\frac{1}{3} x+4$ is the given equation.

We find out slope from the given equation. Slope is the coefficient of x

Slope of given line= $-\frac{1}{3}$

slope of parallel line is same as the slope of given line

Slope of parallel line =  $-\frac{1}{3}$

Now we use point slope formula to get the equation of the line

$y-y_1=m(x-x_1)$, m=-1/3, x1=6 and y1=5

$y-5=-\frac{1}{3}(x-6)$

multiply the fraction inside the parenthesis

$y-5=-\frac{1}{3}x+2$

Add 5 on both sides

$y=-\frac{1}{3}x+7$