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pickupchik [31]

3 years ago

14

On a coordinate grid Ming's house is located 2 blocks to the right and 5 blocks up from (0,0). Joe house is located 3 blocks to

the right and 2 blocks down from Ming's house. What ordered pair describes the location of joe house?

1 answer:

Burka [1]3 years ago

3 0

Answer:

(5, 3)

Step-by-step explanation:

Conventionally, the ordered pairs are (right, up). Then ...

Ming's = (0, 0) + (2, 5) = (2, 5)

Joe's = Ming's + (3, -2) = (2, 5) + (3, -2) = (2+3, 5-2)

Joe's = (5, 3)

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Solve i = Prt for t given that P=300, r=7% and I =105 <br>solve for t

vova2212 [387]

I think it was the same number

6 0

3 years ago

At a campground, a rectangular fire pit is 3 feet by 2 feet. What is the area of the largest circular fire that

AysviL [449]

The area of the largest circular fire pit is 452 square inches.

Explanation:

Given that at a campground, a rectangular fire pit is 3 feet by 2 feet

The radius is given by 1 feet.

<u>Area:</u>

The area of the largest circular fire is given by

$A=\pi r^2$

Substituting the values in the formula, we get,

$A=(3.14)1^2$

$A=3.14 \ ft^2$

Thus, the area of the largest circular fire is 3.14 square feet.

<u>To convert feet to inches:</u>

The feet can be converted into inches by multiplying by 12.

Thus, we have,

$1 \ft= 12 \ inches$

Hence, we have,

$Area= 3.14\times 12^2$

Simplifying,we get,

$Area= 3.14\times144$

$Area=452.16 \ in^2$

Rounding off to the nearest square inch.

Thus, we have,

$Area= 452 \ in^2$

Thus, the area of the largest circular fire pit is 452 square inches.

5 0

3 years ago

On the planet of Mercury, 4-year-olds average 3 hours a day unsupervised. Most of the unsupervised children live in rural areas,

erastova [34]

Answer:

a

The distribution of X is normal

b

$P(X < 1.4) = 0.12654$

c

$P(X > 3.5) = 0.36051$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 3 \ hours$

The standard deviation is $\sigma = 1.4 \ hours$

Generally given from the question that the amount of time spent alone by the population size is normally distributed then then the distribution of X (i.e the amount of time spent by the sample size (the one Mercurian)) will be normally distributed

Generally the probability that the child spend less than one hour in a day is mathematically represented as

$P(X < 1.4) = P(\frac{X - \mu}{\sigma} < \frac{1.4 - \mu}{\sigma} )$

Here $\frac{X - \mu}{\sigma } = Z (The\ standardized\ value\ of\ X)$

So

$P(X < 1.4) = P(Z < \frac{1.4 - 3.0}{1.4} )$

$P(X < 1.4) = P(Z < -1.1429 )$

From the z-table the value of

$P(Z < -1.1429 )=0.12654$

So $P(X < 1.4) = 0.12654$

Generally the percentage of children that spends over 3.5 hours unsupervised is mathematically represented as

$P(X > 3.5) = P(\frac{X - \mu}{\sigma} > \frac{3.5 - \mu}{\sigma} )$

$P(X > 3.5) = P(Z > \frac{3.5 - 3.0}{1.4} )$

$P(X > 3.5) = P(Z > 0.3571 )$

From the z-table the value of

$P(Z >0.3571 )=0.36051$

So $P(X > 3.5) = 0.36051$

5 0

3 years ago

Consider the expression 16y^2 . Select the correct statement:

tiny-mole [99]

Step-by-step explanation:

Given expression is:

$16y^2$

We will solve each statement one by one to see which statements are correct.

<u>If y=3/4, the values of 16y^2 is 12</u>

Putting y = 3/4 in expression

$16y^2 = 16 *(\frac{3}{4})^2 = 16 * \frac{9}{16} = 9$

<u>If y=1/4, the values of 16y^2 is 2</u>

Putting y = 1/4 in expression

<u></u> $16y^2 = 16 *(\frac{1}{4})^2 = 16 * \frac{1}{16} = 1$ <u></u>

<u></u>

<u>If y=3/8, the values of 16y^2 is 4/9</u>

Putting y = 3/8 in expression

<u></u> $16y^2 = 16 *(\frac{3}{8})^2 = 16 * \frac{9}{64} = \frac{9}{4}$ <u></u>

<u></u>

<u>If y=1/8, the values of 16y^2 is 1/4</u>

Putting y = 1/8 in expression

<u></u> $16y^2 = 16 *(\frac{1}{8})^2 = 16 * \frac{1}{64} = \frac{1}{4}$ <u></u>

<u></u>

<u></u>

<u>If y=2/3, the values of 16y^2 is 3/4</u>

Putting y = 2/3 in expression

<u></u> $16y^2 = 16 *(\frac{2}{3})^2 = 16 * \frac{4}{9} = \frac{64}{9}$ <u></u>

<u></u>

<u>Hence,</u>

The correct statement is:

If y=1/8, the values of 16y^2 is 1/4

Keywords: Expressions, variables

Learn more about expressions at:

#LearnwithBrainly

7 0

3 years ago

How many fluorine atoms are found in 1.92 grams of AsF3?

11111nata11111 [884]

First you need to find out how many moles of AsF3 are in 1.92 grams.
The molar mass of AsF3 is 131.918 g/mole so
1.92 g * (1 mole)/(131.918g) = .0146 moles AsF3

Each mole of AsF3 has 6.02 x10^23 molecules of AsF3 and each molecule of AsF3 has 3 flourines, so you need to convert from moles to molecules AsF3 to atoms of F
0.146 moles AsF3 * (6.02 x 10^23 molecules AsF3)/(1 mole AsF3) * (3 atoms F)/(1 molecule AsF3) = 2.64 x 10^22 atoms F

6 0

3 years ago