Answer:
2m^4 - 11m³ + m + 8
Step-by-step explanation:
(2m - 5m³) - (5m + 3m³ - 7m^4) + (8 - 3m³ - 5m^4 + 4m)
2m - 5m³ - 5m - 3m³ + 7m^4 + 8 - 3m³ - 5m^4 + 4m
7m^4 - 5m^4 - 5m³ - 3m³ - 3m³ + 2m - 5m + 4m + 8
2m^4 - 11m³ + m + 8
Answer:
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Step-by-step explanation:
<h2>Thank you! </h2><h2>-Brainly User</h2>
48×56=2,688 that will be the correct answer
Answer:
Therefore (2.30-0.03747)= 2.2625 M of HI remains from an initial concentration of 2.30 M after 4.5 hours.
Step-by-step explanation:
second order reaction: The rate of reaction proportional to the square of the concentration of reactant.
For second order reaction

K is rate constant = 1.6×10⁻³M⁻¹hr⁻¹
a = initial concentration of reactant = 2.30 M
a-x = concentration of reactant after t h
t = time = 4.5 h
Putting the values in the above equation,





Therefore (2.30-0.03747)= 2.2625 M of HI remains from an initial concentration of 2.30 M after 4.5 hours.