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Anni [7]
2 years ago
13

Yall please help me im struggling and i need to pass!!​

Mathematics
2 answers:
vesna_86 [32]2 years ago
3 0

Answer: it is c

Step-by-step explanation:

if it is leaking 3/4 in 1/2 h than it will leak 6/4 in one whole hour

garik1379 [7]2 years ago
3 0
I think it would be C because if it leaked 3/4 every half an hour than you could just add it by itself so 3/4 +3/4=6/4
the denominator will stay the same so that’s the answer
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What is the measure of angle 1?
svp [43]

Answer:

88°

Step-by-step explanation:

Since we have 2 parallel lines, first we use the Corresponding Angles Postulate.

Since angle 2 is corresponding to the 92° angle,

angle 2 = 92°

Now we know that angle 1 and angle 2 are supplementary.

This means:

angle 1 + angle 2 = 180°

<em>(substitute known values)</em>

angle 1 + 92 = 180

<em>(subtract 92 on both sides)</em>

<h2>angle 1 = 88°</h2><h2></h2>

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3 0
2 years ago
Please explain I will give BRAINLIEST!!!!!!
zvonat [6]

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5 0
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8 0
3 years ago
Solve the following system
scZoUnD [109]

Answer:

{x = -4 , y = 2 ,  z = 1

Step-by-step explanation:

Solve the following system:

{-2 x + y + 2 z = 12 | (equation 1)

2 x - 4 y + z = -15 | (equation 2)

y + 4 z = 6 | (equation 3)

Add equation 1 to equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - 3 y + 3 z = -3 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Divide equation 2 by 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Add equation 2 to equation 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+5 z = 5 | (equation 3)

Divide equation 3 by 5:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 3 from equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y+0 z = -2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{-(2 x) + 0 y+2 z = 10 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 2 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = 8 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = -4 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer:  {x = -4 , y = 2 ,  z = 1

4 0
3 years ago
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