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2 years ago

BRAINLIEST FOR RIGHT ANSWER!!

Mathematics

1 answer:

julsineya [31]2 years ago

5 0

Answer: ${\boxed{h(x+4)=\frac{9+3x}{8+x}}}$

Concept:

In a function f(x), it represents a function in terms of x or for x. Therefore, to find the values in the function, substitute values within the parenthesis to solve.

Solve:

Given information

$h(x)=\frac{-3+3x}{4+x}$

Need to find

$h(x+4)$

Substitute (x + 4) to the position of x

$h(x+4)=\frac{-3+3(x+4)}{4+(x+4)}$

Distributive property on the numerator

$h(x+4)=\frac{-3+3x+12}{4+(x+4)}$

Combine like terms

$h(x+4)=\frac{-3+12+3x}{4+4+x}$

$\boxed{h(x+4)=\frac{9+3x}{8+x}}$

Hope this helps!! :)

Please let me know if you have any questions

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Complete Question

1. (12 points) The tennis team at Taft High School has 8 players, and the tennis team at McKinley High School has 7 players. Rebecca is on the team at Taft, and her sister Leah is on the team at McKinley. The two teams are going to play a tournament with 4 rounds. In each round, one player from Taft will play a match against one player from McKinley. Each player can play in at most one match. A schedule for the tournament consists of an ordered list of the names of the players from each school who will play in each of the four rounds. The schedule does not include the results of each match.

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(b) How many schedules include neither sister?

Answer:

$N = 1,411,200$

$M = 302, 400$

Step-by-step explanation:

From the question we are told that

The number of players in Taft High School is t = 8

The number of players in McKinley High School is k = 7

The number of rounds is n = 4

The highest number of match each player can play is w = 1

Generally the total number of schedules is

$N = ^tP_4 * ^k P_4$

$N = ^8P_4 * ^7 P_4$

=> $N = \frac{8!}{(8-4)!} * \frac{7!}{(7-4)!}$

=> $N = \frac{8!}{4!} * \frac{7!}{3!}$

=> $N = \frac{8*7 *6*5*4*3*2*1}{4*3*2*1} * \frac{7*6*5*4*3*2*1}{3*2*1}$

=> $N = 1,411,200$

Generally the number of schedules that include neither of the sisters is mathematically represented as

$M= \ ^{t-1}P_4 *\ ^ {k-1} P_4$

$M= \ ^{8-1}P_4 *\ ^ {7-1} P_4$

=> $M= \ ^{7}P_4 *\ ^ {6} P_4$

=> $M = \frac{7!}{(7-4)!} * \frac{6!}{(6-4)!}$

=> $M = \frac{7!}{3!} * \frac{6!}{2!}$

=> $M = \frac{7 *6*5*4*3*2*1}{3*2*1} * \frac{6*5*4*3*2*1}{2*1}$

=> $M = 302, 400$

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