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larisa [96]
2 years ago
6

BRAINLIEST FOR RIGHT ANSWER!!

Mathematics
1 answer:
julsineya [31]2 years ago
5 0

Answer: {\boxed{h(x+4)=\frac{9+3x}{8+x}}}

Concept:

In a function f(x), it represents a function in terms of x or for x. Therefore, to find the values in the function, substitute values within the parenthesis to solve.

Solve:

<u>Given information</u>

h(x)=\frac{-3+3x}{4+x}

<u>Need to find</u>

h(x+4)

<u>Substitute (x + 4) to the position of x</u>

h(x+4)=\frac{-3+3(x+4)}{4+(x+4)}

<u>Distributive property on the numerator</u>

h(x+4)=\frac{-3+3x+12}{4+(x+4)}

<u>Combine like terms</u>

h(x+4)=\frac{-3+12+3x}{4+4+x}

\boxed{h(x+4)=\frac{9+3x}{8+x}}

Hope this helps!! :)

Please let me know if you have any questions

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Arte-miy333 [17]

The height of the tree is 249.5 feet

<h3>How to determine the height of the tree?</h3>

The given parameters are:

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Let the height of the tree be x.

So, we have:

tan(80) = x/44

Multiply both sides by 44

x = 44 * tan(80)

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10, 4, 8

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3 0
3 years ago
How I simplify this real life expression and show unit analysis?
Anton [14]

The value of the real life expression is, simple interest = $12.5

<h3>How to simplify this real life expression and show unit analysis?</h3>

The real life expression is given as:

simple interest = ($100) (0.05/year) (2.5 years

Divide 1 year by 1 year

simple interest = ($100) (0.05) (2.5)

Rewrite the equation as a product of factors

simple interest = ($100) * (0.05)*  (2.5)

Evaluate the product of 0.05 and 2.5

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Evaluate the product of $100 and 0.125

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Hence, the value of the real life expression is, simple interest = $12.5

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6 0
1 year ago
Can anyone show me how to divide 931/7
Inessa [10]
(You go from left to right)
(Dividend is 931, divisor is 7)
Step 1: Look for a number smaller than 9 that is divisible by 7. 7 is the only one which is smaller than 9 and is divisible by 7. Now that you know 7*1=7, you put 1 above 931 (Dividend)
 Step 2: You subtract that number from the number in tens place. And bring the leftover down.
Step 3: You repeat Step 1 and 2 until either you get a remainder of 0 or the remainder in smaller than the divisor (in this case 7)
(Therefore 931/7=133, quotient=133, remainder=0)
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