The radius of Neptune is 2.48 x 107m. The radial acceleration of an object at the equatorial surface of
The radius of Neptune is 2.48*10^7m. The radical acceleration of an object at the equatorial surface of Neptune is 0.292 m/s2. What is Neptune's period of rotation in seconds?
A.18,000 s
B.1200 s
C.58,000 s
D.9200 s
Answer:
Expanded Notation Form:
234.2
=
200
+
30
+
4
+
0.2
Expanded Factors Form:
234.2
=
2 ×
100
+
3 ×
10
+
4 ×
1
+
2 ×
0.1
Expanded Exponential Form:
234.2 =
2 × 102
+
3 × 101
+
4 × 100
+
2 × 10-1
Word Form:
234.2 =
two hundred thirty-four and two tenths
Answer:C 2
Step-by-step explanation:
The answer would be c , goodluck
Answer:
k(-1) = 7.
Step-by-step explanation:
k(-1) is the value of the function k when x = -1.
You read this off the graph.
Find the value of the point on the graph which corresponds to x = -1. From x = -1 on the horizontal axis move straight up until you meet the graph of k. Now look horizontally to the right and read off the value on the vertical
y-axis
You'll find it is 7.
