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3 years ago

14

– 7 (2W - 5) Simplify by using the distributive property and then combine like terms PLEASE

2 answers:

DENIUS [597]3 years ago

8 0

$\huge\text{Hey there!}$

$\huge\text{-7(2w - 5)}$

$\huge\text{= -7(2w) - 7(-5)}$

$\huge\text{= -14w + 35}$

$\huge\text{You do not have any like terms in this equation}$

$\huge\boxed{\textsf{Answer: -14w + 35}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\huge\boxed{\frak{Amphitrite1040:)}}$

Artemon [7]3 years ago

6 0

-14W + 35. Can’t simplify any further

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4 years ago

If f(x) = -x + 5 and g(x) = x^2, what is (g° (-1)?

ipn [44]

Answer:

$(g\circ f)(-1)=36$

Step-by-step explanation:

We are given the two functions:

$f(x)=-x+5\text{ and } g(x)=x^2$

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$(g\circ f)(-1)$

This is equivalent to:

$=g(f(-1))$

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A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall

Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

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Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

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$\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

$4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)$

Hence, 95% confidence interval for the true mean= (2.54,6.86)

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4 years ago