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stira [4]
3 years ago
15

On the first play, the Wobegone High School football team lost 2 yards. On each of the next 3 plays they lost 2 yards. How many

yards did they total on the 4 plays?
Mathematics
2 answers:
ikadub [295]3 years ago
7 0
They lost 2 yards per play for 4 yards- totaling 8 yards lost.
natali 33 [55]3 years ago
6 0
On the first play, the Wobegone High School football team lost 2 yards. On each of the next 3 plays they lost 2 yards. How many yards did they total on6 total yards in all

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What the answer question now
RUDIKE [14]

Step-by-step explanation:

<em>Here</em><em>,</em>

<em>radius</em><em> </em><em>(</em><em>r</em><em>)</em><em>=</em><em> </em><em>2</em><em>cm</em>

<em>height</em><em>(</em><em>h</em><em>)</em><em>=</em><em>5</em><em>cm</em>

<em>now</em><em>,</em>

<em>according</em><em> </em><em>to the</em><em> </em><em>question</em><em> </em><em>we must</em><em> </em><em>find the</em><em> </em><em>surface</em><em> </em><em>area of cylinder</em><em> </em><em>so</em><em>,</em>

<em>by</em><em> </em><em>formulae</em><em> </em><em>,</em>

<em>a</em><em>=</em><em> </em><em>2.pi.r</em><em>(</em><em>r</em><em>+</em><em>h</em><em>)</em>

<em>now</em><em>,</em><em> </em>

<em>a</em><em>=</em><em> </em><em>2</em><em>×</em><em>3</em><em>.</em><em>1</em><em>4</em><em>×</em><em>2</em><em>(</em><em>2</em><em>+</em><em>5</em><em>)</em>

<em>by</em><em> </em><em>simplifying it we get</em><em>, </em>

<em>The</em><em> </em><em>surface</em><em> </em><em>area of cylinder</em><em> </em><em>is</em><em> </em><em>8</em><em>7</em><em>.</em><em>9</em><em>2</em><em> </em><em>cm</em><em>^</em><em>2</em><em>.</em>

<em><u>Hope it helps</u></em><em><u> </u></em>

6 0
4 years ago
If the mean of A and B is 20, the mean of B and C is 24 and the mean of A,B and C is 18.What is the mean of A and C?
Zielflug [23.3K]

Answer:

the mean of A and C is 10

Step-by-step explanation:

Given;

mean of A and B = 20

mean of B and C = 24

mean of A, B and C = 18

\frac{A + B}{2} = 20\\\\A+ B = 40 ---- (1)\\\\\frac{B + C}{2} = 24\\\\B+ C = 48----(2)\\\\\frac{A+ B+ C}{3} = 18\\\\A+ B+ C= 54---(3)\\\\From (1); \ A = 40 - B\\\\From(2); \ C = 48 - B\\\\\Substitute \ the \ values \ of \ A \ and \ C \ into \ (3)\\\\(40-B) + B + (48-B) = 54\\\\simplify;\\\\(40 + 48) + (B-B-B)= 54\\\\88 -B = 54\\\\-B = 54-88\\\\-B = -34\\\\B = 34

Recall; A = 40 - B

           A = 40 - 34

           A = 6

Also, C = 48 - B

        C = 48 - 34

       C = 14

Therefore, the mean of A and C is calculated as;

= \frac{A + C}{2} \\\\= \frac{6 + 14}{2} \\\\= 10

5 0
3 years ago
PLS OMG!!! i need to pass bro omg pls just please help.
Delvig [45]
Here go to a tutor on your computer usually there some online that can help you with all your Math
problems fast
4 0
3 years ago
Which is a solution to the equation y=3x+1?
Inga [223]
Quite tricky but my answer would be D 
7 0
3 years ago
Read 2 more answers
Given the parent function f(x) = x^2 describe the graph of y = (x-5) ^2 -2
Fiesta28 [93]

Answer:

translated right 5 units and down 2 units

Step-by-step explanation:

its right 5 because, if it is in a parenthesis, it will become the opposite. if it out of the parenthsis it would stay the same.

7 0
3 years ago
Read 2 more answers
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