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Neko [114]
4 years ago
10

A farmer takes 8 days to cultivate a plot of land i ha in area. What area

Mathematics
2 answers:
Verizon [17]4 years ago
7 0

The farmer took 8 days to cultivate one and a half hectares (15000 m^2)

so now divide 15000/8 which equals to 1875. so now we know that it takes him one day to cultivate 1875 m^2 which is 0.1875 hectares.

20 days = 0.1875 x 20

             = 3.7500 hectares

hope it helped!

Kaylis [27]4 years ago
6 0
More information is needed
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An artist is creating a sculpture using bendable metal rods of equal length. One rod is formed into the shape of a square and an
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Check the picture below.

so notice, their perimeter is the same, because the perimeter is just one rod anyway, and all rods are the same length, thus

\bf P_s=P_t\implies 4s=3(s+2)\implies 4s=3s+6\implies s=6

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4 years ago
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How can i solve by completing the square 4r^2-28r=-49
Natalija [7]
To complete the square, the second degree term must have a coefficient of 1.
Since the second degree term here has a coefficient of 4, we start by dividing each term on both sides by 4.

4r^2 - 28r = -49

\dfrac{4r^2}{4} - \dfrac{28}{4}r = -\dfrac{49}{4}

r^2 - 7r = -\dfrac{49}{4}

Now we can complete the square.
First, we need to find what number completes the square.
We take the coefficient of the first degree term, -7 in this case.
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r^2 - 7r + \dfrac{49}{4} = -\dfrac{49}{4} + \dfrac{49}{4}

(r - \dfrac{7}{2})^2 = 0

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4 years ago
How to write 7+2-3-8 in sigma notation
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(7+2-3-8)=0
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Brainliest pts
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7 0
4 years ago
Translations
klemol [59]

1) Reflecting over y=x means (x, y) \longrightarrow (y,x). So, the coordinates of the image are:

V(-3, 0) \longrightarrow V'(0,-3)\\\\W(-1,0) \longrightarrow W'(0, -1)\\\\U(-2,-5) \longrightarrow U'(-5,-2)\\\\X(3,-3) \longrightarrow X'(-3, 3)


2) Rotating 90 degrees counterclockwise about the origin means (x,y) \longrightarrow (-y,x), so the vertices of the image are:

W(0,-1) \longrightarrow W'(1,0)\\\\X(3,-1) \longrightarrow X'(1, 3)\\\\V(0,-3) \longrightarrow V'(3,0)\\\\Y(1, -5) \longrightarrow Y'(5, 1)

3) The vertices of the image are:

C(2,0) \longrightarrow C'(-2, -2)\\\\D(2, 5) \longrightarrow D'(-2, 3)\\\\E(5,4) \longrightarrow E'(1, 2)

6 0
2 years ago
How do I do this? I don't remember how. Help meh pls
vlada-n [284]
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