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ANTONII [103]
3 years ago
12

an italian sausage is 8 inches long how many pieces of sausage can be cut form the 8-inch piece of sausage if each piece is the

be of 2/3 of an inch?
Mathematics
1 answer:
Svetach [21]3 years ago
4 0

Answer: 12

Step-by-step explanation: Find how many thirds are in 8.

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Solve the equation of isosceles triangle and find the x​
Fantom [35]

Answer:

x = 25°

Step-by-step explanation:

2x-10°+2x-10°+100°=180°[sum of angles in a triangle ]

4x+80°=180°

4x=100°

x=25°

5 0
3 years ago
Geometry help plz will mark brainliest.
Alex17521 [72]
I think it's 12x.
I'm not a 100% sure though, but I hope this helps. =^D
5 0
3 years ago
Someone help me with this pls
Mumz [18]

Answer:

There will be approx 283908 hits.

Step-by-step explanation:

A website had 342,000 hits in 2011.

This is a decline of 2.3% from the previous year.

Decline rate = 2.3% or 0.023

So, increase rate will be 1-.023=0.977

Time = 2019-2011=8

We can calculate the answer as:

342000\times(0.977)^{8}

= 342000\times0.83014

= 283907.88 rounding to 283908.

Therefore, there will be approx 283908 hits.

4 0
3 years ago
A car traveling east at 40.0 m/s passes a trooper hiding at the roadside. The driver uniformly reduces his speed to 25.0 m/s in
Anni [7]

Step-by-step explanation:

It is given that,

Initial speed of the car, u = 40 m/s

Final speed of the car, v = 25 m/s

Time taken, t = 3.5 s

(a) We need to find the magnitude and direction of the car’s acceleration as it slows down. It can be calculated using formula as :

a=\dfrac{v-u}{t}

a=\dfrac{25-40}{3.5}

a=-4.28\ m/s^2

The acceleration is in the opposite direction of motion i.e. west.

(b) Let s is the distance the car travel in the 3.5-s time period. It can be calculated using the third equation of motion as

s=\dfrac{v^2-u^2}{2a}

s=\dfrac{25^2-40^2}{2\times (-4.28)}

s = 113.9 meters

Hence, this is the required solution.

6 0
3 years ago
Two trains leave a town at the same time heading in opposite directions. One train is traveling 12 mph faster than the
klemol [59]

Answer:

I'm going to paint you a picture in words of what this looks like on paper.  We have a train leaving from a point on your paper heading straight west.  We have another train leaving from the same point on your paper heading straight east.  This is the "opposite directions" that your problem gives you.  

Now let's make a table:

                distance       =        rate      *       time

Train 1

Train 2

We will fill in this table from the info in the problem then refer back to our drawing.  It says that one train is traveling 12 mph faster than the other train.  We don't know how fast "the other train" is going, so let's call that rate r.  If the first train is travelin 12 mph faster, that rate is r + 12.  Let's put that into the table

              distance        =        rate        *        time

Train 1                                        r

Train 2                                    (r + 12)

Then it says "after 2 hours", so the time for both trains is 2 hours:

         

              distance        =        rate        *        time

Train 1                                        r           *          2

Train 2                                  (r + 12)       *          2

Since distance = rate * time, the distance (or length of the arrow pointing straight west) for Train 1 is 2r.  The distance (or length of the arrow pointing straight east) for Train 2 is 2(r + 12) which is 2r + 24.  The distance between them (which is also the length of the whole entire arrow) is 232.  Thus:

2r + 2r + 24 = 232 and

4r = 208 so

r = 52

This means that Train 1 is traveling 52 mph and Train 2 is traveling 12 miles per hour faster than that at 64 mph

Step-by-step explanation:

3 0
3 years ago
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