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forsale [732]
3 years ago
7

Draw a picture to show how to find 12+37

Mathematics
1 answer:
SpyIntel [72]3 years ago
7 0
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What is the square root of 12 plus the square root of 27?
marysya [2.9K]
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4 years ago
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Let f(x) = x2 – 16 and g(x) = x + 4. Find fg f g and its domain.
Marta_Voda [28]

Answer: fg =x^3+4x^2-16x-64 and


Domain: All real number. All real number or (-\infty,\infty)



Explanation:


fg means product of two given function f(x) and g(x)


where,  

f(x)=x^2-16 and g(x)=x+4


Now, we have to find fg


So, fg=f(x)\times g(x)


Substitute f(x) and f(x)


\Rightarrow (x^2-16)(x+4)


Using distributive property simplify above expression and we get,  

\Rightarrow x^3+4x^2-16x-64


We can see it is cubic polynomial. So, domain of cubic polynomial is all real number.  

Domain: All real number or (-\infty,\infty)



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3 years ago
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Step-by-step explanation:

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Sansa solved the equation 1/2(8x-6)=x+9​
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3 years ago
Find the equation of the line parallel to x+3y = 4 and passing through the point (2, 5)
dmitriy555 [2]

Answer:

The equation of the parallel line is x + 3y = 17

Step-by-step explanation:

Parallel lines have the same slopes and different y-intercept

The form of the equation y = m x + b, where

  • m is the slope of the line
  • b is the y-intercept

∵ The equation of the given line is x + 3y = 4

→ We must put it in the form above to find its slope

→ Subtract x from both sides to move x to the right side

∵ x - x + 3y = 4 - x

∴ 3y = 4 - x

→ Divide both sides by 3 to make the coefficient of y = 1

∴ \frac{3y}{3}=\frac{4}{3}-\frac{1}{3}x

∴ y = \frac{4}{3} -  \frac{1}{3} x

→ Compare it with the form of the equation above

∴ m = -\frac{1}{3}

∵ Parallel lines have the same slopes

∴ The slope of the parallel line is -\frac{1}{3}

→ Put it in the form of the equation

∴ y =  -\frac{1}{3} x + b

→ To find b substitute x and y in the equation by the coordinates

   of a point on the line

∵ The line passes through the point (2, 5)

∴ x = 2 and y = 5

→ Substitute them in the equation

∴ 5 =  -\frac{1}{3} (2) + b

∴ 5 =  -\frac{2}{3} + b

→ Add  \frac{2}{3}  to both sides

∴ \frac{17}{3} = b

→ Substitute it in the form of the equation above

∴ y = -\frac{1}{3} x + \frac{17}{3}

→ Multiply each term by 3

∴ 3y = - x + 17

→ Add x to both sides

∴ x + 3y = 17

∴ The equation of the parallel line is x + 3y = 17

3 0
4 years ago
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