10^2 is 10×10 which is 100
4^2 is 4×4 which is 16
so it simplifies to 100-16×2. By Order Of Operations, parentheses, exponents, multiply and divide, add and subtract 100-16×2 makes 100-32 which is 68
Answer:
(x -3)² +(y -5)² = 36
Step-by-step explanation:
The center is on the vertical line halfway between the given vertical lines, so is at x=3. It is also on the horizontal line through the point (-3, 5), so is at y=5. The center is 9-3=6 from either tangent line, so this is the radius.
For center (h, k) and radius r, the circle's equation is ...
(x -h)² +(y -k)² = r²
For (h, k) = (3, 5) and r=6, the equation is ...
(x -3)² +(y -5)² = 36 . . . . . . . . does not match any choice written here
<h3>
Answer:</h3>

<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Equilibrium</u>
- Equilibrium Constant K
- Concentrations - Denoted in [Brackets]
<h3>
Step-by-step explanation:</h3>
<u>Step 1: Define</u>
[RxN] 2NO₂ ⇆ N₂O₄
[Equilibrium Rate Law] ![\displaystyle K_c = \frac{[N_2O_4]}{[NO_2]^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20K_c%20%3D%20%5Cfrac%7B%5BN_2O_4%5D%7D%7B%5BNO_2%5D%5E2%7D)
NO₂ = 11.95 M
N₂O₄ = 6.05 M
<u>Step 2: Find K</u>
- Substitute [ERL]:
![\displaystyle K_c = \frac{[6.05]}{[11.95]^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20K_c%20%3D%20%5Cfrac%7B%5B6.05%5D%7D%7B%5B11.95%5D%5E2%7D)
- Exponents:
![\displaystyle K_c = \frac{[6.05]}{[142.803]}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20K_c%20%3D%20%5Cfrac%7B%5B6.05%5D%7D%7B%5B142.803%5D%7D)
- Divide:

- Round (Sig Figs):

This value of K tells us that the reactants are favored in the equilibrium reaction (K < 0.1).
For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

Where:
m: It's the slope
b: It is the cut-off point with the y axis
According to the graph, we place two points through which the line passes:

We found the slope:

Substituting we have:

Thus, the equation is of the form:

We substitute one of the points and find the cut-off point:

Finally, the equation is:

ANswer:

The answer is B
a1= 13;an-1+2