Answer:
Part A: The graphs intersect whenever both have the same (x,y) values.
G1 = {(x,y) such that y = 2x}
G2 = {(x,y) such that y = 4x - 2}
G1 ∩ G2 = {(x,y) such that
(x = x) & (y = 2x) & (y = 4x - 2)}
= {(x,y) such that (y = 2x) & (2x = 4x - 2)}
Part B: equation solves to x = 1, but
x = -4, -8 = -16 - 2, false.
x = -3, -6 = -12 - 2, false.
x = -2, -4 = -8 - 2, false.
x = -1, -2 = -4 - 2 = -6, false.
x = 0, 0 = -2, false.
x = 1, 2 = 4 - 2, true.
x = 2, .... do I gotta do the rest???
Part C, solve graphically by drawing straight lines on graph paper, first through (-4,-8) and (4,8), and second through (-4,-14) and (4,14).
They intersect at (1,2).
