Answer:
Part a) 
Part b) 
Step-by-step explanation:
Part a) Write an equation for T (d)
Let
d ----> the number of days
T ---> the time in minutes of the treadmill
we know that
The linear equation in slope intercept form is equal to
where
m is the slope or unit rate
b is the y-intercept or initial value
In this problem we have
The slope or unit rate is
The y-intercept or initial value is
substitute
Part b) Find T (6), the minutes he will spend on the treadmill on day 6
For d=6
substitute in the equation and solve for T
I used Excel to create the tables and the graphs.
I attached both the tables and the graphs.
You should replace the numbers of the x-axis (in both graphs) by the numbers as a fraction of pi. Those numbers are also included in the table, so you should not have problems with that.
Open and see tha file attached with the answer to your question..
Answer:
T = 2
Step-by-step explanation:
Take the given formulaer
I = PRT
And plug in the variables you know (I, P, R)
387.50 = 1,550(.125)T
(12.5% becomes .125 after you divide it by 100, because precents are really just fractions out of 100)
387.50 = 193.75T
T = 2
Answer:
see below
Step-by-step explanation:
DB = 9 units (by counting)
BA = 12 units (by counting)
DA can be found by using the pythagorean theorem
a^2 +b^2 = c^2
BD^2 + BA^2 = DA ^2
9^2 +12^2 = DA^2
81 +144 = DA^2
225 = DA ^2
Take the square root of each side
sqrt(225) = sqrt(DA^2)
15 = DA
LJ = 3 units (by counting)
JK = 4 units (by counting)
LK can be found by using the pythagorean theorem
a^2 +b^2 = c^2
LJ^2 + JK^2 = LK ^2
3^2 +4^2 = LK^2
9 +116 = LK^2
25 = LK ^2
Take the square root of each side
sqrt(25) = sqrt(LK^2)
5 = LK
Scale factor from BAD to JKL
15 to 5
Divide each side by 5
3 to 1
We multiply by 1/3 to go from the big to small
Answer:
78
Step-by-step explanation:
Write out the 13 times tables: 13, 26, 39, 52, 65, 78, ... 78 is the 6th number.
You can also do 13 × 6 which is 78.
Hope this helps!
