Answer:
The last two terms of the expression are
Both the last terms has variable of degree equal to (2+4=6) and (3+3=6).So, the first term must have degree greater than 6.
Correct Options are
Answer:
Step-by-step explanation:
![6k^3+10k^2-56k\\2k(3k^2+5k-28)\\=2k[3k^2+12k-7k-28]\\=2k[3k(k+4)-7(k+4)]\\=2k(k+4)(3k-7)](https://tex.z-dn.net/?f=6k%5E3%2B10k%5E2-56k%5C%5C2k%283k%5E2%2B5k-28%29%5C%5C%3D2k%5B3k%5E2%2B12k-7k-28%5D%5C%5C%3D2k%5B3k%28k%2B4%29-7%28k%2B4%29%5D%5C%5C%3D2k%28k%2B4%29%283k-7%29)
common factor is 3k-7
9514 1404 393
Answer:
3. C(−1, −5), D(2, −5)
Step-by-step explanation:
The given points are 2 -(-1) = 3 units apart horizontally, so the remaining points will need to be 18/3 = 6 units below, vertically. Translating the given points down 6 gives ...
D = A -(0, 6) = (2, 1) -(0, 6) = (2, -5)
C = B -(0, 6) = (-1, 1) -(0, 6) = (-1, -5)
The two points required to make a rectangle with an area of 18 square units are ...
C(-1, -5), D(2, -5)
_____
The area of a rectangle is the product of length and width. If the area is 18 square units, and the width is 3 units, then the length must be 6 units. 3×6=18.
Answer:????
Step-by-step explanation:
i don’t know shister
