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Yuki888 [10]
3 years ago
13

2) Lucy spent $15, 500 to purchase a new car this year. Lucy can expect her car to depreciate at a rate of 7% per year.

Mathematics
1 answer:
Lelechka [254]3 years ago
5 0

Answer:

<u>Equation: V = C * (1 - r)^t</u>

<u>Answer: $ 8,066.37</u>

Step-by-step explanation:

Let's recall that depreciation on a car can be determined by the formula:

V = C * (1 - r)^t , where:

V is the value of the car after t years,

C is the original cost

r is the rate of depreciation

t is the number of years of utilization of the car

Therefore, we have:

V = C * (1-r)^t

V = 15,500 * (1 - 0.07)⁹

V = 8,066.37 (rounding to the next cent)

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Answer:

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3 years ago
A company invests $32000. after 4 years of growth at the same rate each year, the investment is worth $42692. find the annual gr
Nostrana [21]

Answer:

R = 33.35%

Step-by-step explanation:

that is the solution above

6 0
2 years ago
2. How many different hands of 3 cards hands be chosen from a deck of 52 cards?
krok68 [10]

Answer:

There are 132,600 ways are there.

<h3>Explained:</h3>

We note that there 52 ways to choose the first card, 51 ways to choose the second card, and 50 ways to choose the third card, for a total of 52*51*50=132,600 ways

7 0
3 years ago
The diagram is not drawn to scale
Afina-wow [57]

Answer:

3060 cm^2

Step-by-step explanation:

First, let's find the areas of the trapezoids.

  • \frac{34+6}{2}*15
  • 40/2 * 15
  • 20*15
  • 300 * 2  
  • 600

Next, let's find the area of the bases (the top rectangle and bottom rectangle).

  • Top: 6 × 30 = 180
  • Bottom: 34 × 30 = 1020
  • 1020 + 180 = 1200.

After that, we find the surface area of the side rectangles.

  • 17 × 30 = 510
  • 25 × 30 = 750
  • 510 + 750 = 1260.

Lastly, we add 1260, 1200, and 300 together.

  • 1260+1200+600
  • 3060

Therefore, the surface area should be 3060 cm^2.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

3 0
2 years ago
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Simplify the expression
Nataliya [291]
Answer:
x^35

Explanation:
5 x 7 = 35
4 0
3 years ago
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