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Greeley [361]
4 years ago
7

A newspaper editor starts a retirement savings plan in which $225 per month is deposited at the beginning of each month into an

account that earns an annual interest rate of 6.6% compounded monthly. Find the value (in dollars) of this investment after 20 years. (Enter a number. Round your answer to the nearest cent.)
Mathematics
1 answer:
qwelly [4]4 years ago
7 0

Answer: the value of this investment after 20 years is $112295.2

Step-by-step explanation:

We would apply the formula for determining future value involving deposits at constant intervals. It is expressed as

S = R[{(1 + r)^n - 1)}/r][1 + r]

Where

S represents the future value of the investment.

R represents the regular payments made(could be weekly, monthly)

r = represents interest rate/number of interval payments.

n represents the total number of payments made.

From the information given,

Since there are 12 months in a year, then

r = 0.066/12 = 0.0055

n = 12 × 20 = 240

R = $225

Therefore,

S = 225[{(1 + 0.0055)^240 - 1)}/0.0055][1 + 0.0055]

S = 225[{(1.0055)^240 - 1)}/0.0055][1.0055]

S = 225[{(3.73 - 1)}/0.0055][1.0055]

S = 225[{(2.73)}/0.0055][1.0055]

S = 225[496.36][1.0055]

S = $112295.2

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Step-by-step explanation:

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For this case we have the following expression:
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Answer:

Q1: f'(x) = (-6x^8 + 2x^4 + 4)(48x^7) + (6x^8)(-48x^7 + 8x^3)

Q2: f'(x) = (6x^4)(18x^2 - 54x^8) + (6x^3 - 6x^9 + 3)(24x^3)

Step-by-step explanation:

The derivative of the product of two functions is:

f(x) = v(x)u(x)

f'(x) = v(x)u'(x) + u(x)v'x)

The derivative is the product of the first function and the derivative of the second function added to the product of the second function and the derivative of the first function.

Q1: The function you are given is:

f(x) = 6x^8(-6x^8 + 2x^4 + 4)

You can think of that function as the product of functions

u(x) = 6x^8 and v(x) = -6x^8 + 2x^4 + 4

We first find the derivatives of functions u and v:

u'(x) = 48x^7 and v'(x) = -48x^7 + 8x^3

Now we follow the rule above:

f'(x) = v(x)u'(x) + u(x)v'x)

f'(x) = (6x^8)(-48x^7 + 8x^3) + (-6x^8 + 2x^4 + 4)(48x^7)

Use the commutative property to change the order of the sum.

f'(x) = (-6x^8 + 2x^4 + 4)(48x^7) + (6x^8)(-48x^7 + 8x^3)

This is the solution you have.

Q2: The function you are given is:

f(x) = 6x^4(6x^3 - 6x^9 + 3)

You can think of that function as the product of functions

u(x) = 6x^4 and v(x) = 6x^3 - 6x^9 + 3

We first find the derivatives of functions u and v:

u'(x) = 24x^3 and v'(x) = 18x^2 - 54x^8

Now we follow the rule above:

f'(x) = v(x)u'(x) + u(x)v'x)

f'(x) = (6x^4)(18x^2 - 54x^8) + (6x^3 - 6x^9 + 3)(24x^3)

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The giraffe is about 5 feet tall
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