3 years ago

Find the largest integer $n$ for which $12^n$ evenly divides $20!$.

Mathematics

2 answers:

fredd [130]3 years ago

8 0

9514 1404 393

Answer:

n = 8

Step-by-step explanation:

12 = 2² · 3

20! = 2¹⁸ · 3⁸ · [larger primes]

The highest power of 12 that is a factor of 20! is 12^8, limited by the number of factors of 3 there are.

n = 8

jok3333 [9.3K]3 years ago

7 0

Answer:

n = n

Step-by-step explanation:

explanation is on the top and he/she correct

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