Find the largest integer $n$ for which $12^n$ evenly divides $20!$.
2 answers:
9514 1404 393
Answer:
n = 8
Step-by-step explanation:
12 = 2² · 3
20! = 2¹⁸ · 3⁸ · [larger primes]
The highest power of 12 that is a factor of 20! is 12^8, limited by the number of factors of 3 there are.
n = 8
Answer:
n = n
Step-by-step explanation:
explanation is on the top and he/she correct
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