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3 years ago

Which best describes an example of an n-type semiconductor?

Physics

2 answers:

Amanda [17]3 years ago

8 0

Answer:

A.) It uses phosphorus so that electrical conduction is due to the movement of electrons.

Explanation:

An n-type semiconductor is a material in which electrical conduction is due to the movement of electrons

-N-type dopants- arsenic, phosphorus, and antimony

Brainliest?

nata0808 [166]3 years ago

6 0

An N-Type semiconductor will always have an excess electron which is more famous for the term valence electrons. It is one of the part which makes a p-n junction the structure of a diode a basic type of semiconductor device. A P-type semiconductor on the other hand has missing electrons or most widely known as valence holes. When applied a voltage bias of correct polarity and intensity between both ends of the junction you are able to close the gap between the junction allowing the excess valence electron to pass through the p type material inducing current with process, in application lighting up the diode.

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A sample has a mass of 15 g and a volume of 3mL

bezimeni [28]

Thanks for sharing. The density of the sample
is 5 g/cm³. Do you have a question to ask ?

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4 years ago

Scientists want to place a 3400.0 kg satellite in orbit around Mars. They plan to have the satellite orbit at a speed of 2480.0

BaLLatris [955]

Answer:

Part a)

$r = 6.96 \times 10^6 m$

Part b)

$F_g = 3.004 \times 10^3 N$

Part c)

$a = 0.88 m/s^2$

Part d)

$v = \frac{2480}{2} = 1240 m/s$

Explanation:

Part a)

As we know that the orbital speed of the satellite is given as

$v = 2480 m/s$

now we will have

$v = \sqrt{\frac{GM_{mars}}{r}}$

now we have

$M_{mars} = 6.4191 \times 10^{23} kg$

$R_{mars} = 3.397 \times 10^6 m$

now we have

$2480 = \sqrt{\frac{(6.67 \times 10^{-11})(6.4191 \times 10^{23})}{r}}$

$r = 6.96 \times 10^6 m$

Part b)

Here force between mars and satellite is the gravitational attraction force which is given as

$F_g = \frac{GM_{mars} m}{r^2}$

$F_g = \frac{(6.67\times 10^{-11})(6.4191 \times 10^{23})(3400)}{(6.96\times 10^6)^2}$

$F_g = 3.004 \times 10^3 N$

Part c)

Acceleration of satellite is the ratio of gravitational force and mass of the satellite

$a = \frac{F_g}{m}$

$a = \frac{3004}{3400}$

$a = 0.88 m/s^2$

Part d)

As we know by III law of kepler

$\frac{T_1^2}{T_2^2} = \frac{r_1^3}{r_2^3}$

here we know that T2 = 8 T1

$(\frac{1}{8})^2= \frac{r_1^3}{r_2^3}$

$\frac{r_1}{r_2} = (\frac{1}{2})^2$

so we have

$r_2 = 4r_1$

as we know that speed is given as

$v = \sqrt{\frac{GM}{r}}$

so we can say since radius is orbit becomes 4 times so the orbital speed must be half

$v = \frac{2480}{2} = 1240 m/s$

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4 years ago

The frequency of the fundamental of the guitar string is 320 Hz. At what speed c do waves move along that string?

viktelen [127]

Complete question is The frequency of the fundamental of the guitar string is 320 Hz. At what speed c do waves move along that string? wavelength is 40 cm.

Answer:

128 m/s

Explanation:

In case where fundamental frequency is given, the speed with waves travel along the string can be calculated using the following formula:

v = f (2L) where L is the length of the string (L = λ/2)

⇒v= f λ

f = 320 Hz (given)

λ = 40 cm = 0.40 m

Substitute the values:

⇒ v = 320 Hz × 0.40 m= 128 m/s

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3 years ago

What is the correct explanation of Newton's Third Law of Motion?

viva [34]

Answer:

Explanation:

it explains the most, and it is the correct theorem

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3 years ago

Read 2 more answers

A teacher applles a force to a wall and becomes axhausted.<br> Explanation:

Finger [1]

Because they are using all of there energy to apply the force

Hope this helps — xoxo

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3 years ago